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Artemon [7]
3 years ago
5

URGENT!!! Can someone help me with this? It’s volume of cones!!!

Mathematics
1 answer:
LiRa [457]3 years ago
8 0

Answer:

1232 m^3 to nearest whole number.

Step-by-step explanation:

The volume of a cone = 1/3 π r^2 h     where r = radius of base and h = height.

The radius of the base = 1/2 * 14 = 7m.

The height can be found by using the Pythagoras theorem:

25^2 = h^2 + 7^2

h^2 = 625 - 49 = 576

h = √576 =  24m

So the volume = 1/3 π *  7^2 * 24

=  1231.504 m^3.

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LUCKY_DIMON [66]
Same line so the correct answer is b
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3 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 436.0 gram setting. It
Vilka [71]

Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, \bar{x} = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}

We use one-tailed(left) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{429 - 436}{\frac{23}{\sqrt{40}} } = -1.92

Now, z_{critical} \text{ at 0.05 level of significance } = -1.64

Since,  

z_{stat} < z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.

8 0
3 years ago
A sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters. Give a point est
xxTIMURxx [149]

Answer:

Point estimate for the population variance = 3.92 * 10^{-3} .

Step-by-step explanation:

We are given that a sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters ;

       X                       X - Xbar                                         (X-Xbar)^{2}

      1.13            1.13 - 1.188 = -0.058                                 3.364 * 10^{-3}

      1.15            1.15 - 1.188 = -0.038                                 1.444 * 10^{-3}    

      1.15            1.15 - 1.188 = -0.038                                 1.444 * 10^{-3}

      1.24           1.24 - 1.188 = 0.052                                 2.704 * 10^{-3}

      1.27           1.27 - 1.188 = 0.082                               <u>  6.724 * </u>10^{-3}<u>    </u>

                                                                    \sum (X-Xbar)^{2} <u>= 0.01568   </u>

Firstly, Mean of above data, Xbar = \frac{\sum X}{n} = \frac{1.15+1.24+1.15+1.27+1.13}{5} = 1.188

Point estimate of Population Variance = Sample variance

                                                               = \frac{\sum (X-Xbar)^{2}}{n-1} = \frac{0.01568}{4} = 3.92 * 10^{-3} .

Therefore, point estimate for the population variance = 3.92 * 10^{-3} .

       

5 0
3 years ago
Read 2 more answers
Lynn can type 60 words per minute. If she types for 30 minutes, how many words does she type in all?
Crazy boy [7]

Answer:1800 words

Step-by-step explanation:

Multiply how many words per minute she types by how many minutes she types. In this case 60x30=?. The easy way to do this is drop the 2 zeros and do  6x3=18. In the original equation we dropped the 2 zeros. Now we add them back on the back of the 18 and get 1800.

7 0
3 years ago
5. In an arithmetic sequence, the fifth term is 44 and the ninth term is 80.(a) Find the common difference. (b) Find the first t
natulia [17]

Step-by-step explanation:

first you should do is that find the common difference which is 9

6 0
1 year ago
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