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3 years ago

6th grade math help me pleaseeee

Mathematics

2 answers:

shtirl [24]3 years ago

7 0

Answer:

i think C because both of the percentages shown should get what the question is asking

Step-by-step explanation:

Llana [10]3 years ago

3 0

The correct answer is C. 78

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Jasmine filled her bag with 12 strawberries. George filled his bag with 6 times as many strawberries as jasmine. How many strawb

Brilliant_brown [7]

Answer:

There are <u>72 strawberries</u> in George's bag.

Step-by-step explanation:

Given:

Jasmine filled her bag with 12 strawberries. George filled his bag with 6 times as many strawberries as jasmine.

Now, to find the number of strawberries are in George's bag.

Number of strawberries in Jasmine bag = 12.

George filled his bag with 6 times as many strawberries as jasmine.

So, number of strawberries of George's bag is:

$12\times 6$

$=72.$

Therefore, there are 72 strawberries in George's bag.

5 0

2 years ago

Read 2 more answers

P+12=17 what does p equal in this situation

victus00 [196]

Answer:

Step-by-step explanation:

5+12= 17

8 0

3 years ago

Read 2 more answers

Find the distance between the two points rounding to the nearest tenth (if

lana [24]

Answer:

5.7

Step-by-step explanation:

Creating the point into a triangle, both sides a 4.

As the Pythagorean theorem goes, a^2+b^2=c^2

4^2+4^2=

16+16=

The square root of 32 is about 5.7

The distance between the points is about 5.7 units

6 0

3 years ago

Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin

saw5 [17]

Treat $\mathcal C$ as the boundary of the region $\mathcal S$ , where $\mathcal S$ is the part of the surface $z=2xy$ bounded by $\mathcal C$ . We write

$\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r$

with $\mathbf f=(y+7\sin x,z^2+9\cos y,x^3)$ .

By Stoke's theorem, the line integral is equivalent to the surface integral over $\mathcal S$ of the curl of $\mathbf f$ . We have

$\nabla\times\mathbf f=(-2z,-3x^2,-1)$

so the line integral is equivalent to

$\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S$
$=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv$

where $\mathbf s(u,v)$ is a vector-valued function that parameterizes $\mathcal S$ . In this case, we can take

$\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)$

with $0\le u\le1$ and $0\le v\le2\pi$ . Then

$\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv$

and the integral becomes

$\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv$
$=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi$ <span />

4 0

3 years ago

HELP ASAP PLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLS

notka56 [123]

Answer:

15/6

Step-by-step explanation:

5 0

2 years ago