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madam [21]
2 years ago
6

6x+2y=18 can someone please help me with this

Mathematics
1 answer:
Mice21 [21]2 years ago
8 0

Answer: m=-3

Step-by-step explanation: I know okie i jast want points

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What is m∠B?<br><br>A.51<br><br>B..129<br><br>C.134<br><br>D.141
san4es73 [151]

Answer:

I think it 129 If not try 4

7 0
3 years ago
Using the standard 28/36 guidelines, what is the maximum mortgage payment allowed for someone with
Nitella [24]

The maximum mortgage payment allowed for someone with an annual salary of $83,750 would be $2512.50 per month.

<h2><u>What is the standard 28/36 guidelines?</u></h2>

To determine, using the standard 28/36 guidelines, what is the maximum mortgage payment allowed for someone with an annual salary of $83,750, the following calculation must be made:

  • Annual salary x 36% / months = X
  • ((83750 x 36) / 100) / 12 = X
  • (3,015,000 / 100) / 12 = X
  • 30150 / 12 = X
  • 2512.50 = X

Therefore, the maximum mortgage payment allowed for someone with an annual salary of $83,750 would be $2512.50 per month.

Learn more about maths in brainly.com/question/20589209

4 0
2 years ago
Solve for W: P=2L + 2W<br><br>A. W=P-L<br>B. W= 1/2P - L<br>C. W= 1/2 P + L<br>D. W= 2P - L​
svetlana [45]

Answer:

B

Step-by-step explanation:

P=2L+2W

P-2L=2W (Subtract 2L from both sides of the equation)

2W=P-2L (Symmetric Property of Equality)

W=\frac{P-2L}{2} (Divide both sides of the equation by 2)

W=\frac{P}{2} -\frac{2L}{2} ("Split" the fractions)

W=\frac{1}{2}P-L (Simplify)

Hope this helps!

4 0
2 years ago
PLEASE HELP!!!!! How many 4-digit numbers divisible by 5, all of the digits of which are even, are there?
saul85 [17]

Answer:

I assume you know Arithmetic Progression .

so, we have to find the first and last 4-digit number divisible by 5

first = 1000 ,  last =  9990

we have a formula,   a_{n} = a + (n-1)d

here, a_{n} is the last 4-digit number divisible by 5.

n is the number of 4-digit even numbers divisible by 5

d is the common difference between the numbers, which is 10 in this case

a is the first 4-digit number divisible by 5

9990 = 1000 + (n-1)*10

899 = n-1

n = 900

Hence, there are 900 4-digit even numbers divisible by 5

7 0
2 years ago
Order from greatest to least 1.202;1.29;1.02
Reptile [31]

Answer:

1.29, 1.202, 1.02

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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