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3 years ago

Find the value of -8 - 12 - (-20). 24 -40 16 0

Mathematics

2 answers:

Nataly [62]3 years ago

5 0

D) 0
Hope that helped!

TiliK225 [7]3 years ago

3 0

Answer:

it's = 0

you have to use the steps of maths

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Llana [10]

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3 years ago

PLSSSSSS HELPPPP!!!!!Determine the area of the composite figure shown.

katrin2010 [14]

Answer: 26.13yards^2

Step-by-step explanation:

To find the area of the bottom part we can use the diameter.

6 yards. Divide it by half to have the Radius.

Now we use the formula to find the area of a circle which is

A = 3.14*R^2 Pie times radius squared.

A = 3.14*3^2

A = 3.14*9

A = 28.26 Now that we have the area of the circle divide it by 2.

14.13

Now to find the area of an isosceles triangle we use the formula

A = Base * Height Divided by 2.

A = 6*4/2

A = 24/2

A = 12

12 + 14.13 = 26.13

7 0

3 years ago

Find the 82nd term of the following sequence.<br><br> -32, -27, -22, ....

My name is Ann [436]

The 82nd term for the sequence would be -4

6 0

3 years ago

One square megameter is equal to 1.0×106 square kilometers. How many square megameters are in 9,000,000 square kilometers?

Firlakuza [10]

9, because one square megameter is equal to one million square kilometers.

7 0

3 years ago

Read 2 more answers

Solve the triangle A = 2 B = 9 C =8

VARVARA [1.3K]

Answer:

$\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}$

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

$\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}$

Then, given the sides a=2, b=9, and c=8.

$\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}$

For B:

$\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}$ $\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}$

3 0

1 year ago