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Readme [11.4K]
3 years ago
11

How many moles are in 5.30 X 1023 molecules of H2O?

Chemistry
1 answer:
arlik [135]3 years ago
6 0

Answer:

0.880 (0.88039867109 to be exact)

Explanation:

To convert from molecules to moles, simply divide by Avogadro's number which is 6.02 x 10^23

So, 5.30x10^23/6.02x10^23 = 0.880

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What happens if kinetic energy of a gas is lowered
k0ka [10]

Answer:

"If you lower the kinetic energy of a gas its temperature will decrease because temperature is a measure of the average kinetic energy of a substance."

Explanation:

7 0
3 years ago
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oxygen is a common oxidizing agent in nature. what change in the oxidation number of oxygen must occur if it is to be an oxidizi
Minchanka [31]

Answer is: the oxidation number of oxygen must decrease.

Oxidizing agent is element (substance) that gain electrons in chemical reaction.

For example, balanced chemical reaction: C + O₂ → CO₂.

Oxygen change oxidation number from 0 to oxidation number -2 (reduction) and carbon change from 0 to +4 (oxidation)

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3 years ago
CH4 + 202 → CO2 + 2H2O<br> How many moles O2 needed to produce 4 moles of H2O?
shepuryov [24]
<h3>Answer:</h3>

4 mol O₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced]   CH₄ + 2O₂ → CO₂ + 2H₂O

[Given]   4 mol H₂O

[Solve]   x mol O₂

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol H₂O → 2 mol O₂

<u>Step 3: Stoichiometry</u>

  1. Set up conversion:                    \displaystyle 4 \ mol \ H_2O(\frac{2 \ mol \ O_2}{2 \ mol \ H_2O})
  2. Multiply/Divide:                          \displaystyle 4 \ mol \ O_2
7 0
3 years ago
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What mass of NH3 in grams must be used to produce 1.81 tons of HNO3 by the Ostwald process, assuming an 80.0 percent yield in ea
Alex17521 [72]

The three reactions involved in the Ostwald process for the conversion of NH3 to HNO3 are:

4NH3(g) + 5O2(g) ==> 4NO(g) + 6H2O(l)   ------(1)

2NO(g) + O2(g) ==> 2NO2(g)  ------------------------(2)

3NO2(g) + H2O(l) ==> 2HNO3(aq) + NO(g) ---(3)

Mass of HNO3 produced = 1.81 tons

In grams, the mass of HNO3 = 1.81*2000*453.6 = 1642032 g

Molar mass of HNO3 = 63 g/mol

Thus, # moles of HNO3 produced = 1642032/63 = 26064 moles

Based on the stoichiometry of reaction (3):

Theoretical moles of NO2 = 1.5(Moles HNO2 ) = 1.5(26064) = 39096

Assuming 80% yield:

Actual moles of NO2 = 0.8*39096 = 31277 moles

Based on the stoichiometry in reaction (2):

Theoretical moles of NO = 31277 moles

Assuming 80% yield:

Actual moles of NO = 0.8*31277 = 25022 moles

Bases on stoichiometry in reaction(3):

Moles of NH3 = 25022 moles

Assuming 80% yield:

Actual moles of NH3 required = 0.8*25022 = 20018 moles

Mass of NH3 required = 20018 moles * 17 g/mole = 340306 g = 340.31 kg

7 0
4 years ago
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HELP IM TIMED!!!!!!!!!
victus00 [196]

Answer:

A. 1.3 bison/mi^2

Explanation:

4500 bison divided by 3472 sq miles is 1.3 bison per mile squared.

7 0
3 years ago
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