H2O, one Oxygen in the middle, surrounded by 2 hydrogen, usually close to each-other, which gives it polarity
Answer:
a) 35°C, the temperature on a hot summer day
b) -11.11°C, the temperature on a cold winter day
c) a 38.88°C fever
d) a furnace operating at 1011.11°C
e) 523.67°F ( theoretically the lowest attainable temperature )
Explanation:
- °C = ( °F - 32 ) / 1.8
- °F = ( 1.8 * °C ) +32
a) 95°F ⇒ °C = ( 95 - 32 ) / 1.8 = 35°C
b) 12°F ⇒ °C = ( 12 - 32 ) / 1.8 = -11.11°C
c) 102°F ⇒ °C = ( 102 -32 ) / 1.8 = 38.88°C
d) 1852°F ⇒ °C = ( 1852 -32 ) / 1.8 = 1011.11°C
e) 273.15°C ⇒ °F = ( 1.8 * 273.15 ) + 32 = 523.67°F
Answer:
106 mL
Explanation:
In order to be able to answer this question, you must understand what the density of a substance tells you.
The density of a substance is nothing more than the mass of that substance that occupies one unit of volume.
In your case, the density of ethanol is given in Grams per milliliter, which means that one unit of volume will be
1 mL
.
So, ethanol has a density of
0.785 g mL
−
1
, which is equivalent to saying that if you take exactly
1 mL
of ethanol and weigh it, you will end up with a mass of
0.785 g
.
Now, you know that the volume you're using has a mass of
83.3 g
. Well, if you get
0.785 g
for every
1 mL
of ethanol, it follows that this much mass will correspond to a volume of
83.3
g ethanol
⋅
ethanol's density
1 mL
0.785
g ethanol
=
106.11 mL
Rounded to three sig figs, the answer will be
V
ethanol
=
106 mL
Hope this helps
<span>Take the inversion of density: 1mL/13.6 g and multiply it by the conversion factor 453.6 g/ 1 lb and the given 5.00 lb. Units for mass (grams) and units for weight (lbs) cancel leaving only units of volume. I believe it should be 167 mL or 0.167 L</span>
Answer:
Argon 7.89693x10^25 atoms
Gold 4.1949252x10^25 atoms
Carbon Monoxide 34.55149 moles
Potassium oxide 1.6 moles
Calcium 4.4969x10^24 atoms
Explanation:
Its done with dimensional analysis i can not put the full work here because it would look to sloppy
