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Olegator [25]
3 years ago
7

Could anyone pls give the ans of 8th pls?

Mathematics
2 answers:
drek231 [11]3 years ago
5 0
The answer is: -5/9
34kurt3 years ago
4 0

Answer:

-5/9

Step-by-step explanation:

\frac{5}{9} + ____ = 0

subtract \frac{5}{9} from both sides of the equation

-\frac{5}{9}               -\frac{5}{9}

leaving you with

____ = - \frac{5}{9}

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If X=3, What is the area of a triangle with sides, 6x ,7x, and 21x? A.117 in² B.378 in² C.189 in² D. 58.5 in²
AURORKA [14]

Answer:

The given sides does not form a triangle

Step-by-step explanation:

The given sides does not form a triangle

We know the triangle property which states that the sum of any two sides of the triangle should be greater than the third side.

Here given th esides of the triangle are 6x,7x,21x

6x+7x=13x < 21x

for any value of x the above equation does not satisfy.

8 0
3 years ago
Y varies directly with x, and y = 15 when x = 3. What is the value of x when y = 4?
TiliK225 [7]
When x = 3 , y = 15 , divide both by 3.
When x= 1 , y = 5. Now multiply both by 4/5
When x = 4/5 , y=4
8 0
3 years ago
Read 2 more answers
SOMEONE PLEASE HELP ME. WILL MARK BRAINLIEST
fredd [130]

Answer:

Function

Step-by-step explanation:

The following is a <em><u>one-on-one function</u></em> since neither the domain nor the range is being repeated.

6 0
2 years ago
Read 2 more answers
What are rational numbers and how do you tell the difference between integers? Please answer what are rational numbers first.
Maslowich

1. A rational number is a number that can be written as a fraction.

For example: 1/3, 5/7, 90/666, etc

Note: Any integer can be written as a fraction.

Look:

5 = 5/1 = rational

-14 = -14/1 = rational

2. There is no difference between a rational and integer.

6 0
3 years ago
Passing through (2, - 2) and perpendicular to the line whose equation is y= 5x+2
jonny [76]

Step-by-step explanation:

Hey there!!!

Here,

Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.

The equation of a straight line passing through point is,

(y - y1) = m1(x - x1)

Now, put all values.

(y  + 2) = m1(x - 2)

It is the 1st equation.

Another equation is;

y = 5x +2........(2nd equation).

Now, Comparing it with y = mx + c, we get;

m2=5

As per the condition of perpendicular lines,

m1×m2= -1

m1 × 5 = -1

Therefore, m2= -1/5.

Keeping the value of m1 in 1st equation.

(y + 2) =  \frac{ - 1}{5} (x - 2)

Simplify them.

5(y + 2) =  - x + 2

5y + 10 =  - x + 2

x + 5y + 8 = 0

Therefore the required equation is x+5y+8= 0.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
3 years ago
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