Answer:
Step-by-step explanation:
The ticket price of the item after applying coupon B first and then coupon A is $65.45
Coupons reduce the ticket price of an item.
<u><em>Ticket price</em></u><u><em> after </em></u><u><em>coupon B i</em></u><u><em>s applied </em></u>
An item costs $80. After applying the coupon B which gives, $3 off the price, the cost of the item reduces to $77 ($80 - $3).
The ticket price of the item after coupon B is applied is $77
<em><u>Ticket price </u></em><em><u>after c</u></em><em><u>oupon A </u></em><em><u>is applied </u></em>
The item costs $77 when coupon B is applied. If the discount is 15% off on coupon A, it means that the item costs 85%( 100 - 15%) of its initial price.
Ticket Price of the item = percentage price x price of the item after the first coupon B was applied
85% x $77
0.85 x $77 = $65.45
A similar question was solved here: brainly.com/question/17413216?referrer=searchResults
Answer:
Option A
Step-by-step explanation:
We need to solve out ,
We can write it as ,
On simplyfing further,
On solving the above equation , we will get ,
Now we know that the value of modulus is never negative so when we will put x is equal to 2 on the RHS we will get -20 which is not possible . Therefore , the extraneous root is -2 .
<u>Option</u><u> </u><u>A </u><u>is </u><u>correct</u><u> </u><u>.</u>
Answer:- a.The given expression is equivalent to 
Given expression:- ![[\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%283xy%5E%7B-5%7D%29%5E3%7D%7B%28x%5E%7B-2%7Dy%5E2%29%5E%7B-4%7D%7D%5D%5E%7B-2%7D)
![=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B%283%29%5E3x%5E3y%5E%7B-5%5Ctimes3%7D%7D%7Bx%5E%7B-2%5Ctimes-4%7Dy%5E%7B2%5Ctimes-4%7D%7D%5D%5E%7B-2%7D.........%28a%5Em%29%5En%3Da%5E%7Bmn%7D)
![=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B27x%5E3y%5E%7B-15%7D%7D%7Bx%5E8y%5E%7B-8%7D%7D%5D%5E%7B-2%7D)
![=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}](https://tex.z-dn.net/?f=%3D%5B27x%5E%7B3-8%7Dy%5E%7B-15-%28-8%29%7D%5D%5E%7B-2%7D............%5Cfrac%7Ba%5Em%7D%7Ba%5En%7D%3Da%5E%7Bm-n%7D)
![=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}](https://tex.z-dn.net/?f=%3D%5B27x%5E%7B-5%7Dy%5E%7B-7%7D%5D%5E%7B-2%7D%3D%2827%29%5E%7B-2%7D%28x%5E%7B-5%7D%29%5E%7B-2%7D%28y%5E%7B-7%7D%29%5E%7B-2%7D.........%28a%5Em%29%5En%3Da%5E%7Bmn%7D)
Thus a. is the right answer.
