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VikaD [51]
3 years ago
10

The time required for one cycle, a complete motion that returns to its starting point, is called the _____.

Physics
1 answer:
GenaCL600 [577]3 years ago
8 0

Answer: the Time that is required is called a period

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You are measuring the mass of different chemicals to get ready to conduct an experiment.
vova2212 [387]

Answer:

B) grams

The SI unit for mass is grams.

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3 years ago
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An astronaut holds a rock 100m above the surface of Planet X. The rock is then thrown upward with a speed of 15m/s, as shown in
Harlamova29_29 [7]

The acceleration due to gravity of the planet X is 1 m/s².

The given parameters;

  • height above the ground, h = 100 m
  • initial velocity of the rock, u = 15 m/s
  • time of motion of the rock, t = 10 s

The acceleration due to gravity is calculated as follows;

h = ut - \frac{1}{2} gt^2\\\\100 = 15(10) - (0.5\times 10^2)g\\\\100 = 150 - 50g\\\\50g = 150-100\\\\50g = 50\\\\g = 1 \ m/s^2

Thus, the acceleration due to gravity of the planet X is 1 m/s²

Learn more here: brainly.com/question/24564606

7 0
2 years ago
An electric appliance is connected by wires to a 240-volt source of voltage. If the combined resistance of the appliance and wir
uranmaximum [27]
  • Voltage=V=240V
  • Resistance=R=12ohm
  • Current be I

Apply ohms law

  • V=IR
  • 240=12I
  • I=240/12
  • I=20A
6 0
2 years ago
How long will it take to go 150,000 m traveling at 50 km/hr
Vanyuwa [196]
150 km / 50 km/h = 3h

5 0
3 years ago
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A rocket with a mass of 62,000 kg (including fuel) is burning fuel at the rate of 150 kg/s and the speed of the exhaust gases is
mezya [45]

Answer:

h≅ 58 m

Explanation:

GIVEN:

mass of rocket M= 62,000 kg

fuel consumption rate =  150 kg/s

velocity of exhaust gases v= 6000 m/s

Now thrust = rate of fuel consumption×velocity of exhaust gases

=6000 × 150 = 900000 N

now to need calculate time t = amount of fuel consumed÷ rate

= 744/150= 4.96 sec

applying newton's law

M×a= thrust - Mg

62000 a=900000- 62000×9.8

acceleration a= 4.71 m/s^2

its height after 744 kg of its total fuel load has been consumed

h= \frac{1}{2}at^2

h= \frac{1}{2}4.71\times4.96^2

h= 58.012 m

h≅ 58 m

4 0
3 years ago
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