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4 years ago

What holds strands of peptidoglycan together??

Chemistry

1 answer:

Amiraneli [1.4K]4 years ago

6 0

What holds a peptidoglycan together is NAM and NAG sugars+ different amino acids.

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What is the difference in energy between an electron in 1s and an electron in 4s.

Andre45 [30]

Answer:

Explanation:

An electron in 4s is farther away from nucleus and it has higher energy when compared to electron from 1s.

5 0

3 years ago

What is the mass of 1.7 × 1023 atoms of zinc

fiasKO [112]

We are given with a compound, Zinc (Zn) having a 1.7 x 10 ^23 atoms. We are tasked to solve for it's corresponding mass in g. We need to find first the molecular weight of Zinc, that is

Zn= 65.38 g/mol

Not that 1 mol=6.022x10^{23} atoms, hence,

1.7 x 10 ^23 atoms x 1 mol/6.022x10^{23} atoms x65.38 g/ 1mol

=18.456 g of Zn

Therefore, the mass of Zinc 18.456 g

3 0

3 years ago

What is the value of youth participating in volunteering

bearhunter [10]

Answer:

Volunteering helps the teens gain new skills necessary for the job market such as leadership, communication skills, dependability, time management, and decision making.

Explanation:

The Hidden Values of Volunteering

Learn New Skills. One fantastic thing that volunteering can offer you is a new understanding of your own abilities. ...

Test for Your Future. An added side effect of volunteering is that it gives you an opportunity to try out possible careers, majors, and opportunities. ...

Meet New People. ...

Accomplish Something Important.

HOPE THIS HELPED ❤✨

3 0

3 years ago

What is the answer A,B,C,D

SVETLANKA909090 [29]

(A) Gamma waves have the highest energy

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4 years ago

A compound contains 1.2 g of carbon, 3.2 g of oxygen and 0.2g of hydrogen. Find the formula of the compound

Karolina [17]

Answer:

The empirical formula of the compound is $C_{0.504}HO_{1.008}$ .

Explanation:

We need to determine the empirical formula in its simplest form, where hydrogen ( $H$ ) is scaled up to a mole, since it has the molar mass, and both carbon ( $C$ ) and oxygen ( $O$ ) are also scaled up in the same magnitude. The empirical formula is of the form:

$C_{x}HO_{y}$

Where $x$ , $y$ are the number of moles of the carbon and oxygen, respectively.

The scale factor ( $r$ ), no unit, is calculated by the following formula:

$r = \frac{M_{H}}{m_{H}}$ (1)

Where:

$m_{H}$ - Mass of hydrogen, in grams.

$M_{H}$ - Molar mass of hydrogen, in grams per mole.

If we know that $M_{H} = 1.008\,\frac{g}{mol}$ and $m_{H} = 0.2\,g$ , then the scale factor is:

$r = \frac{1.008}{0.2}$

$r = 5.04$

The molar masses of carbon ( $M_{C}$ ) and oxygen ( $M_{O}$ ) are $12.011\,\frac{g}{mol}$ and $15.999\,\frac{g}{mol}$ , then, the respective numbers of moles are: ( $r = 5.04$ , $m_{C} = 1.2\,g$ , $m_{O} = 3.2\,g$ )