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guajiro [1.7K]
3 years ago
7

A 15.50 gram sample of a gas exerts a pressure of 1.40 atmospheres when held in an 8.00 liter at 22 °C. What is the molar mass (

grams/mol) of the gas?
Chemistry
1 answer:
Lostsunrise [7]3 years ago
3 0

Answer:

33.5 g/mol

Explanation:

PV=nRT

(1.40 atm)(8.00 L)=n(0.08206)(295 K)

n=0.463 mol

15.50 g/0.463 mol=33.5 g/mol

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What is the difference between mass and weight?
Olin [163]

Explanation:

The mass of an object is a measure of the object's inertial property, or the amount of matter it contains. The weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it. The pull of gravity on the earth gives an object a downward acceleration of about 9.8 m/s2.

7 0
3 years ago
How many grams are in 1 mole of Ar?
Ilia_Sergeevich [38]

Answer: 39.948 grams

Explanation:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Ar, or 39.948 grams

3 0
3 years ago
If I have 8 moles of Iron atoms in the products, how many moles of Iron atoms did I start with?
Vika [28.1K]

Answer: You started with 8

Explanation: the amount of products is equal to the amount of reactants

6 0
3 years ago
Read 2 more answers
24g of methane were burned in an excess of air. What mass of water would be produced in the reaction assuming complete combustio
expeople1 [14]

Answer:

54g of water

Explanation:

Based on the reaction, 1 mole of methane produce 2 moles of water.

To solve this question we must find the molar mass of methane in order to find the moles of methane added. With the moles of methane and the chemical equation we can find the moles of water produced and its mass:

<em>Molar mass CH₄:</em>

1C = 12g/mol*1

4H = 1g/mol*4

12g/mol + 4g/mol = 16g/mol

<em>Moles methane: </em>

24g CH₄ * (1mol / 16g) = 1.5 moles methane

<em>Moles water:</em>

1.5moles CH₄ * (2mol H₂O / 1mol CH₄) = 3.0moles H₂O

<em>Molar mass water:</em>

2H = 1g/mol*2

1O = 16g/mol*1

2g/mol + 16g/mol = 18g/mol

<em>Mass water:</em>

3.0moles H₂O * (18g / mol) =

<h3>54g of water</h3>
8 0
3 years ago
How much faster does ethane (C2H6) gas travel compared to chlorine gas?
zimovet [89]

Answer:

\large \boxed{\text{54 $\, \%$ faster }}

Explanation:

v_{\text{rms}} \propto \sqrt{\dfrac{3RT}{M}

if temperature is constant.  

v_{\text{rms}} \propto \sqrt{\dfrac{1}{M}

if we are comparing two gases,

\dfrac{v_{2}}{v_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}

Let chlorine be Gas 1 and ethane be Gas 2

Data:

M₁ =  70.91 g/mol

M₂ = 30.07 g/mol

Calculation

\begin{array}{rcl}\dfrac{v_{2}}{v_{1}} & = & \sqrt{\dfrac{M_{1}}{M_{2}}}\\\\& = & \sqrt{\dfrac{70.91}{30.07}}\\\\& = & \sqrt{2.358}\\\\& = & \mathbf{1.54}\\\end{array}\\\text{Ethane molecules travel at 1.54 times the speed of chlorine molecules}\\\text{or $\large \boxed{\textbf{54 $\%$ faster }}$ than chlorine molecules}

5 0
3 years ago
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