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Bingel [31]
3 years ago
15

If the diameter of a circle is 124 centimeters, then what is the radius.

Mathematics
2 answers:
zhenek [66]3 years ago
6 0

Answer:

radius = 62 cm

Step-by-step explanation:

radius = diameter/2

radius = 124/2 = 62 cm

Veseljchak [2.6K]3 years ago
6 0

Answer:

the radius 62

Step-by-step explanation:

the radius is really just the diameter split in half.

So, 124/2 = 62

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Emily has $3.15 worth of dimes and quarters. She has twice as many dimes as quarters. Determine the number of dimes and the numb
Cerrena [4.2K]

Answer:

The number of dimes is <u>14</u> and the number of quarters is <u>7</u>.

Step-by-step explanation:

Given:

Emily has $3.15 worth of dimes and quarters.

<em><u>She has twice as many dimes as quarters.</u></em>

Now, to determine the number of dimes and the number of quarters.

Let the number of quarters be x.

And the number of dimes be  2x.

So, the total worth of dimes and quarters = $3.15.

Now, to get the number of dimes and quarters:

According to question:

0.10(2x)+0.25x=3.15

0.20x+0.25x=3.15

0.45x=3.15

<em>Dividing both sides by 0.45 we get:</em>

x=7.

<em>Thus, the number of quarters</em> = 7.

<em>So, the number of dimes</em> = 2x=2\times 7=14.

Therefore, the number of dimes is 14 and the number of quarters is 7.

6 0
3 years ago
An author argued that more basketball players have birthdates in the months immediately following July​ 31, because that was the
Lady_Fox [76]

Answer:

There is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency.

Step-by-step explanation:

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A Chi-square test for goodness of fit will be used in this case.

The hypothesis can be defined as:

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<em>Hₐ</em>: The observed frequencies are not same as the expected frequencies.

The test statistic is given as follows:

 \chi^{2}=\sum{\frac{(O-E)^{2}}{E}}

The values are computed in the table.

The test statistic value is \chi^{2}=128.12.

The degrees of freedom of the test is:

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Compute the <em>p</em>-value of the test as follows:

p-value < 0.00001

*Use a Chi-square table.

p-value < 0.00001 < α = 0.05.

So, the null hypothesis will be rejected at any significance level.

Thus, there is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency.

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