Question

There are three sequential operations (Station 1, Satiation 2, and Station 3) in a process. Incoming applications go to station 1 first, then to Station 2, finally to station 3, and then leave the process. There are 1 resources in Station 1, 2 resources in Station 2, and 3 resources in Station 3. The capacity of EACH SINGLE RESOURCE in these stations is 3, 5, and 5 applications per day. The last 3 numbers are the capacity of a single resource (a resource unit) in each of the three stations (resource pools), respectively. This process wors 24 hours a day. Compute the theoretical flow time.

Answer 1

Answer:

1 hour 19 mins

Explanation:

The computation of the  theoretical flow time is shown below;

The sequence of operation  represent as a Station 1 -> Station 2 -> Station 3

Now

The capacity of each station is

= number of resources × capacity of each resource

Particulars           Station 1         Station 2         Station 3

resources               1                      2                    3

the capacity of

each resource        3                      5                     5

the capacity of

each station           3                       20                  15

Now The theoretical flow time for each station is  

Station 1 = 60 ÷ (3 ÷ 1) = 20 mins

Station 2 = 60 ÷ (5 ÷ 2) = 24 mins

Station 3 = 60 ÷ (5 ÷ 3) = 35.92 mins

So,

Total theoretical flow time is

= 20 + 24 + 35.92

= 79.92 mins

= 1 hour 19 mins