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katovenus [111]
3 years ago
13

Which of the following is the name of the process scientists use to gain

Physics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

b

Explanation:

.

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The value of the normal force exerted on a 2,000 gram block on a table
kobusy [5.1K]

Answer:

N = 19.6 N

Explanation:

Given that,

Mass of a block, m = 2000 g

1 kg = 1000 g

It means, 2000 g = 2kg

We need to find the value of normal force on the block on a table. Normal force is balanced by the weight of the block as follows :

N = mg, g is acceleration due to gravity

N = 2 kg × 9.8 m/s²

N = 19.6 N

So, the normal force acting on the block is 19.6 N.

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Which statement correctly describes the differences between positive and negative acceleration?
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In my opinion, the third answer makes the most sense
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The diagram shows a person holding a bow and arrow. Which will most likely increase the kinetic energy in this system? a not rel
Fantom [35]

Answer:

b. Increasing the mass of the arrow.

Explanation:

The formula is K=1/2mv^2. Increasing the mass also increases the kinetic energy.

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Shown here is a portion of the activity table. Based
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A lightning flash releases about 1010J of electrical energy. Part A If all this energy is added to 50 kg of water (the amount of
zavuch27 [327]

Answer:

water is in the vapor state,

Explanation:

We must use calorimetry equations to find the final water temperatures. We assume that all energy is transformed into heat

        E = Q₁ + Q_{L}

Where Q1 is the heat required to bring water from the current temperature to the boiling point

      Q₁ = m c_{e} ( T_{f} -T₀)

      Q₁ = 50 4180 (100 - 37)

      Q₁ = 1.317 10⁷ J

Let's calculate the energy so that all the water changes state

     Q_{L}  = m L

     Q_{L}  = 50 2,256 106

    Q_{L}  = 1,128 10⁸ J

Let's look for the energy needed to convert all the water into steam is

     Qt = Q₁ + Q_{L}  

     Qt = 1.317 107 + 11.28 107

     Qt = 12,597 10⁷ J

Let's calculate how much energy is left to heat the water vapor

     ΔE = E - Qt

     ΔE = 10¹⁰ - 12,597 10⁷

     ΔE = 1000 107 - 12,597 107

     ΔE = 987.4 10⁷ J

With this energy we heat the steam, clear the final temperature

     Q = ΔE = m c_{e} ( T_{f}-To)

    ( T_{f}-T₀) = ΔE / m c_{e}

      T_{f} = T₀ + ΔE / m c_{e}

      T_{f} = 100 + 987.4 10⁷ / (50 1970)

      T_{f} = 100 + 1,002 10⁵

      T_{f} = 1,003 10⁵ ° C

This result indicates that the water is in the vapor state, in realizing at this temperature the water will be dissociated into its hydrogen and oxygen components

4 0
3 years ago
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