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rewona [7]
3 years ago
15

An object is 16.0cm to the left of a lens. The lens forms an image 36.0cm to the right of the lens. a) What is the focal length

of lens? (5 pts) b) Sketch the ray diagram considering an extended object? (Spts) c) Calculate the magnification? Describe the image type?

Physics
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Answer:

-2.25

Real and inverted image

Explanation:

u = Object distance =  16 cm

v = Image distance = 36 cm

f = Focal length

Lens Equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{16}+\frac{1}{36}\\\Rightarrow \frac{1}{f}=\frac{13}{144}\\\Rightarrow f=\frac{144}{13}=11.07\ cm

Focal length of the lens is 11.07 cm. Positive value indicates the lens is a convex lens

Magnification

m=-\frac{v}{u}\\\Rightarrow m=-\frac{36}{16}\\\Rightarrow m=-2.25

Since magnification is negative the image inverted

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here is the question : A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 60.0m/s. Air resistance may be ignored,so the water balloon is in free fall after it leaves the throwers hand. a) What is its speed after falling for 2.00s? b) How far does it fall in 2.00s? c) What is the magnitude of its velocity after falling 10.0m?

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