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rewona [7]
3 years ago
15

An object is 16.0cm to the left of a lens. The lens forms an image 36.0cm to the right of the lens. a) What is the focal length

of lens? (5 pts) b) Sketch the ray diagram considering an extended object? (Spts) c) Calculate the magnification? Describe the image type?

Physics
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Answer:

-2.25

Real and inverted image

Explanation:

u = Object distance =  16 cm

v = Image distance = 36 cm

f = Focal length

Lens Equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{16}+\frac{1}{36}\\\Rightarrow \frac{1}{f}=\frac{13}{144}\\\Rightarrow f=\frac{144}{13}=11.07\ cm

Focal length of the lens is 11.07 cm. Positive value indicates the lens is a convex lens

Magnification

m=-\frac{v}{u}\\\Rightarrow m=-\frac{36}{16}\\\Rightarrow m=-2.25

Since magnification is negative the image inverted

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The Bowen's reaction series illustrates the relationship between temperature, chemical composition and mineral structure.

The series is made up of a continuous and discontinuous end through which magmatic composition can be understood as temperature changes.

  • The left part is the discontinuous end while the right side is the continuous series.
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In a choir practice room, two parallel walls are 5.70 m apart. The singers stand against the north wall. The organist faces the
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Answer:

4.98 m

Explanation:

Given that

Width of the mirror, d = 0.6 m

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Distance between the singer and the organist, S = 5.7 + 0.78 = 6.48 m

Width of north wall, D?

Using the simple relationship

D/S = d/s, on rearranging

D = dS /s

D = (0.6 * 6.48) / 0.78

D = 3.888 / 0.78

D = 4.98 m

Therefore, we can conclude that the Width of north wall is 4.98 m

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Split complementary colors.

Analogous colors.

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Tetradic harmonies.

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Explanation:

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