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3 years ago

All help is needed, thanks

Chemistry

1 answer:

yarga [219]3 years ago

3 0

Answer:

smoke
marshmallow
paint
Body spray

Explaination:

Firstly, what are colloids?

Colloids are a mixture of two substances:

one of those substances are insoluble and inseparable

There are 4 types of colloids:

Sol- Solid in a liquid
Emulsion- Liquid in a liquid
Foam- Gas in solid/liquid
Aerosol- Solid/liquid in gas

So on to the answers:

Smoke consists of solid and gas and since the solid is being carried by the gas, it is a solid in a gas (aerosol)
Marshmellow consists of tiny air bubbles and sugar(solid), the air bubbles is inside the solid making it a gas in a solid (foam)
Body spray turns gas into liquid after spraying it through the can, making it a liquid in a gas (aerosol)
Paint dries up to become solid which makes it a solid is a liquid (sol)

Hope y'all understand

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The question is in the picture below

Rus_ich [418]

Answer:

$\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3$

Explanation:

Hess's Law of Constant Heat Summation states that if a chemical equation can be written as the sum of several other chemical equations, the enthalpy change of the first chemical equation is equal to the sum of the enthalpy changes of the other chemical equations. Thus, the reaction that involves the conversion of reactant A to B, for example, has the same enthalpy change even if you convert A to C, before converting it to B. Regardless of how many steps it takes for the reactant to be converted to the product, the enthalpy change of the overall reaction is constant.

With Hess's Law in mind, let's see how A can be converted to 2C +E.

$\bf{\text{A} \rightarrow 2\text{B}}$ (Δ $\text{H}_1$ ) -----(1)

Since we have 2B, multiply the whole of II. by 2:

$\bf{2\text{B} \rightarrow 2\text{C} +2\text{D}}$ (2Δ $\text{H}_2$ ) -----(2)

This step converts all the B intermediates to 2C +2D. This means that the overall reaction at this stage is $\text{A} \rightarrow 2\text{C} +2\text{D}$ .

Reversing III. gives us a negative enthalpy change as such:

$\bf{2\text{D} \rightarrow \text{E}}$ (-Δ $\text{H}_3$ ) -----(3)

This step converts all the D intermediates formed from step (2) to E. This results in the overall equation of $\text{A} \rightarrow 2\text{C} +\text{E}$ , which is also the equation of interest.

Adding all three together:

$\text{A} \rightarrow 2\text{C}+\text{E}$ ( $\bf{\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3 }$ )

Thus, the first option is the correct answer.

Supplementary:

To learn more about Hess's Law, do check out: brainly.com/question/26491956

4 0

1 year ago

When dipentyl ether is treated with HI, what type of reaction occurs? both SN1 and SN2 SN2 E1 SN1 E2

masha68 [24]

Answer:

SN2

Explanation:

The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.

The second step of the reaction may proceed by either SN1 or SN2 mechanism depending on the structure of the ether. Methyl and primary ethers react with HI by SN2 mechanism while tertiary ethers react with HI by SN1 mechanism. Secondary ethers react with HI by a mixture of both mechanisms.

Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.

7 0

3 years ago

Which of the following phenomena would be associated with the Big Bang theory.

Murrr4er [49]

Answer: justin

Explanation:

It is becasue im rich right

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3 years ago

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2 years ago

All help is needed, thanks​

All help is needed, thanks