How many moles of air molecules are contained in a 2.00 L flask at 98.8 kPa and 25.0 degrees of C show work plz
1 answer:
Answer:
7.97 x 10⁻² mol.
Explanation:
- To calculate the no. of moles of a gas, we can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm (P = 98.8 kPa = 0.975 atm).
V is the volume of the gas in L (V = 2.0 L).
n is the no. of moles of the gas in mol (??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K).
T is the temperature of the gas in K (T = 25°C + 273 = 298 K).
<em>∴ n = PV/RT </em>= (0.975 atm)(2.0 L)/(0.0821 L.atm/mol.K)(298 K) = <em>7.97 x 10⁻² mol.</em>
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