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2 years ago

How many moles of air molecules are contained in a 2.00 L flask at 98.8 kPa and 25.0 degrees of C show work plz

Chemistry

1 answer:

larisa [96]2 years ago

7 0

Answer:

7.97 x 10⁻² mol.

Explanation:

To calculate the no. of moles of a gas, we can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 98.8 kPa = 0.975 atm).

V is the volume of the gas in L (V = 2.0 L).

n is the no. of moles of the gas in mol (??? mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K).

T is the temperature of the gas in K (T = 25°C + 273 = 298 K).

∴ n = PV/RT = (0.975 atm)(2.0 L)/(0.0821 L.atm/mol.K)(298 K) = 7.97 x 10⁻² mol.

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Witch two chemists organized the elements based on properties suck as how the elements reacts or whether they are solid or liqui

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Answer:

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Explanation:

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2 years ago

Which law relates to the ideal gas law?

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Answer: The law that related the ideal gas law is $\frac{V_1}{n_1}=\frac{V_2}{n_2}$

Explanation:

There are 4 laws of gases:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

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$P_1V_1=P_2V_2$

Charles' Law: This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

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$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Gay-Lussac Law: This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

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$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

Avogadro's Law: This law states that volume is directly proportional to number of moles at constant temperature and pressure.

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$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

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