Question

How many moles of air molecules are contained in a 2.00 L flask at 98.8 kPa and 25.0 degrees of C show work plz

Answer 1

Answer:

7.97 x 10⁻² mol.

Explanation:

• To calculate the no. of moles of a gas, we can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 98.8 kPa = 0.975 atm).

V is the volume of the gas in L (V = 2.0 L).

n is the no. of moles of the gas in mol (??? mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K).

T is the temperature of the gas in K (T = 25°C + 273 = 298 K).

∴ n = PV/RT = (0.975 atm)(2.0 L)/(0.0821 L.atm/mol.K)(298 K) = 7.97 x 10⁻² mol.