The pair of points that are equal to x coordinates is (0,0)
The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>
The equation of the function is given as:
Expand the function
Reorder the terms
Factor the expression
Factor out x -1
Expand
Factorize
](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Bx%28x%20%2B%203%29%20%2B%202%28x%20%2B%203%29%5D%28x%20-%201%29)
Factor out x + 2
The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
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12 can go into 54 only 4 times because 4•12 is 48. Now 56-48=6 so this is the remainder 6/12 wish can be simplified to 1/2 so your answer is 4 1/2 or 4.5. Hope this helps <333
Answer:
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Step-by-step explanation:
A.
<span>GCF(10; 2) = 2 /</span>factors of 10: 1, 2, 5, 10; factors of 2: 1, 2/
B.
GCF(4; 6) = 2 /factors of 4: 1, 2, 4; factors of 6: 1, <span>2, 3, 6/</span>
C.
GCF(6; 12) = 6 /factors of 6: 1, 2, 3, 6; factors of 12: 1, <span>2, 3, 4, 6, 12/</span>
D.
GCF(2; 24) = 2 <span>/factors of 2: 1, 2; factors of 24: 1, <span>2, 3, 4, 6, 8, 12, 24/</span>
</span>Answer: A, B and D.
