Answer:
BD = 22, DC = 11√3
Step-by-step explanation:
In triangle ABC, ∠B = 45°, ∠C = 90°. Hence:
∠A + ∠B + ∠C = 180° (sum of angles in a triangle)
∠A + 45 + 90 = 180
∠A + 135 = 180
∠A = 45°
Using sine rule to find BC:

In triangle BCD, ∠D = 30°, ∠C = 90°. Hence:
∠D + ∠B + ∠C = 180° (sum of angles in a triangle)
∠B + 30 + 90 = 180
∠B + 120 = 180
∠B = 60°
Using sine rule to find BD:

Using sin rule to find DC:

Answer:
c) j=2 and h=4
Step-by-step explanation:
h+h+j+4+j+4=20
3h+3h+j+1+j+1=30
2h+2j+8=20
6h+2j+2=30
multiply the first equation by -3
-6h-6j-24=-60
this equals
-6h-6j=-36
6h+2j=28
-4j=-8
j=2
Since j=2
2h+2(2)+8=20
2h+12=20
2h=8
h=4

Find the first derivatives:

.
Solve the system

:

. The second equation has solutions

and then

and you have two points

.
Find the first derivatives:

and calculate
![\Delta=\left| \left[\begin{array}{cc}24&-24\\-24&12y\end{array}\right]\right |=24\cdot 12y-(-24)^2=288y-576](https://tex.z-dn.net/?f=%5CDelta%3D%5Cleft%7C%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D24%26-24%5C%5C-24%2612y%5Cend%7Barray%7D%5Cright%5D%5Cright%20%7C%3D24%5Ccdot%2012y-%28-24%29%5E2%3D288y-576)
.
Since

and

,

is a point of maximum and

.
Since

and

,

is a point of minimum and

.
You would divide 127 by 8 then multiply that answer by three sirts each.
<h2><u>
Answer:</u></h2><h3>

</h3><h2><u>
</u></h2><h2><u>
Solution Steps:</u></h2>
______________________________
<h3>1.) Graph each equation:</h3>
(I've included the graphs below.)
So your answer is c,
.
______________________________