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Vanyuwa [196]
3 years ago
8

Hii please help i’ll give brainliest!!

Mathematics
1 answer:
tino4ka555 [31]3 years ago
4 0

Answer:

third one i think soo ( a push or pull acting on an object )

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Write an equation for the line passing through the points (0,3) and (-9,0) using Y=mx+b format.
Valentin [98]

Answer:

y = \frac{1}{3}x + 3

Step-by-step explanation:

y = mx + b

y = mx + 3 (the y-intercept was given (0,3))

\frac{3 - 0}{0 + 9} = \frac{3}{9} = \frac{1}{3}

y = \frac{1}{3}x + 3

7 0
3 years ago
At a restaurant, three salads, two sandwiches, and one drink cost $17.75. One salad, one sandwich, and three drinks cost $10.75.
Leno4ka [110]

Answer:

A salad costs $2.50

A sandwich costs $4.50

A drink costs $1.25

Step-by-step explanation:

Let x represent the salad, y represent the sandwich, and z represent the drink.

Since three salads, two sandwiches, and one drink cost $17.75:

3x + 2y + z = 17.75  (1)

Since one salad, one sandwich, and three drinks cost $10.75:

x + y + 3z = 10.75  (2)

Since a salad costs twice as much as a drink:

x = 2z  (3)

Multiply the equation 2 by -2 then, sum the equation 1 and equation 2:

-2x - 2y - 6z = -21.50

3x + 2y + z = 17.75

→ x - 5z = -3.75

Replace the x with 2z using equation 3:

2z - 5z = -3.75

-3z = -3.75

z = 1.25

x = 2z → x = 2.50

x + y + 3z = 10.75 → 2.50 + y + 3.75 = 10.75 → y + 6.25 = 10.75 → y = 4.50

5 0
2 years ago
Please help me, haha...
sashaice [31]
Yup the answer is C !!
3 0
2 years ago
Solve this answer<br> 5/3 + 2/5
salantis [7]
5/3+2/5=25/15+6/15=31/15=2 1/15

2 1/15 or 31/15

5 0
3 years ago
Read 2 more answers
An analyst from an energy research institute in California wishes to precisely estimate a 99% confidence interval of the average
Lena [83]

Answer:

190

Step-by-step explanation:

Data provided in the question:

Confidence level = 99%

Therefore,

α = 1% = 0.01

[ from standard normal table ]

z-value for z_{\frac{\alpha}{2}}= z_{\frac{0.01}{2}}= = 2.58

Margin of error, E = $0.06

Standard deviation, σ = $0.32

Now,

n = (\frac{z_{0.005}\sigma}{E})^2

Here,

n is the sample size (or the minimum number of gas stations  )

on substituting the respective values, we get

= (\frac{z_{0.005}\sigma}{E})^2

= (\frac{2.58\times0.32}{0.06})^2

= 13.76²

= 189.3376 ≈ 190

Hence,

minimum number of gas stations that she should include in her sample is 190

5 0
3 years ago
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