Answer:
2y-4x
Step-by-step explanation:
That would be the cube root of (x+5)^11.
If desired, this could be reduced to the cube root of (x+5)^9*(x+5)^2, which would be
(x+5)^3*(x+5)^(2/3)
Answer:
The quotient of two integers may not always be an integer.
Therefore, I do not agree when a student says that the sum difference, product, and quotient of two are always integers.
Step-by-step explanation:
The student is not largely correct!
The sum, difference, and product of two integers is indeed always an integer.
But, the quotient of two integers may not always be an integer.
- For example, the quotient of integers 4 and 2 will be an integer.
i.e.
4/2 = 2
- But, if we take the quotient of 2 and 3, the result will not be an integer.
i.e.
2/3 = 0.67
Therefore, I do not agree when a student says that the sum difference, product, and quotient of two are always integers.
First;
-8≤2x-4
-4≤2x
-2≤x
Then;
2x-4<4
2x<8
x<4
-2≤x<4
C is the correct answer.
