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3 years ago

13

Using what you know about air pressure and the water cycle, explain how hurricanes form. Why are there certain places on Earth m

ore prone to hurricanes than others?

1 answer:

Yuki888 [10]3 years ago

4 0

Hurricanes form when hot air and cold air start colliding above water and they start to form a tornado but there is water in the tornado. Certain places on earth are more susceptible to hurricanes because they are closer to the coastlines. For example, in Iowa, and Illinois, they have a lower chance of a hurricane, while Florida, and Washington have a higher rate because they are along the ocean. Hope this helps.

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What is the effect on climate from these factors??

fenix001 [56]

The effect on the climate is that the climate goes up

7 0

3 years ago

A truck is traveling east at 80 km/h. At an intersection 32 km ahead, a car is traveling north at 50 km/h. How long after this m

nirvana33 [79]

The time elapsed when the vehicles are closest to each other is 20 min.

The given parameters:

Speed of the truck, u = 80 km/h
Distance, d = 32 km
Speed of the car, v = 50 km/h

<h3>Principles of relative speed</h3>

The time elapsed when the cars are close to each other is calculated by applying the principles of relative speed.

$(V_r) t = d\\\\V_r^2 = 50^2 + 80^2\\\\V_r =\sqrt{50^2 + 80^2} \\\\V_r = 94.34 \ km/h$

$94.34 t = 32\\\\t = \frac{32}{94.34} \\\\t = 0.34 \ hr\\\\t \approx 20 \min$

Thus, the time elapsed when the vehicles are closest to each other is 20 min.

Learn more about relative velocity here: brainly.com/question/24430414

3 0

2 years ago

A mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. It ta

My name is Ann [436]

Answer:

a). $K=528.92 \frac{N}{m}$

b). $m=4.84kg$

Explanation:

a).

The work of the spring is find by the formula:

$w_s =\frac{1}{2}*k*x^2$

So knowing the work can find the constant K'

$3.2J =\frac{1}{2}*k*(0.11m)^2$

Solve for K'

$K=\frac{2*W_s}{x^2}=\frac{2*3.2J}{0.11m^2}$

$K=528.92 \frac{N}{m}$

b).

The force of the spring realice a motion so using the force and knowing the accelerations can find the mass

$F=m*a$

$m=\frac{F}{a}=\frac{K*x}{a}$

$m=\frac{528.9*0.11m}{12m/s^2}$

$m=4.84kg$

8 0

3 years ago

What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor

const2013 [10]

Complete Question

An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.

What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.

Answer:

The torque is $\tau = 34.3 \ N\cdot m$

Explanation:

From the question we are told that

The mass of the steel ball is $m = 3.0 \ kg$

The length of arm is $l = 70 \ cm = 0.7 \ m$

The mass of the arm is $m_a = 4.0 \ kg$

Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as

$r = \frac{l}{2}$

=> $r = \frac{ 0.7}{2}$

=> $r = 0.35 \ m$

Generally the magnitude of torque about the athlete shoulder is mathematically represented as

$\tau = m_a * g * r + m * g * L$

=> $\tau = 4 * 9.8 * 0.35 + 3 * 9.8 * 0.70$

=> $\tau = 34.3 \ N\cdot m$

5 0

3 years ago

How long must a tow truck apply a force of 600 N to increase the speed of a 1,500 kg car at rest to 2 m/s?

slega [8]

The time the truck must apply the given force to increase its speed to given value is 5 s.

The given parameters;

<em>applied force, F = 600 N</em>
<em>mass of the truck, m = 1,500 kg</em>
<em>speed of the truck, v = 2 m/s</em>

The force applied to the truck is determined by Newton's second law of motion; <em>which states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.</em>

F = ma

$F = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{1500 \times 2}{600} \\\\t = 5 \ s$

Thus, the time the truck must apply the given force to increase its speed to given value is 5 s.

Learn more here:brainly.com/question/1988795

7 0

2 years ago