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raketka [301]
3 years ago
10

In order to place a satellite into orbit, it requires enough fuel to supply the necessary mechanical energy. Into what types of

mechanical energy does the fuel get transformed?
Physics
1 answer:
nexus9112 [7]3 years ago
6 0

When a satellite is revolving into the orbit around a planet then we can say

net centripetal force on the satellite is due to gravitational attraction force of the planet, so we will have

F_g = F_c

\frac{GM_pM_s}{r^2} = \frac{M_s v^2}{r}

now we can say that kinetic energy of satellite is  given as

KE = \frac{1}{2}M_s v^2

KE = \frac{GM_sM_p}{2r}

also we know that since satellite is in gravitational field of the planet so here it must have some gravitational potential energy in it

so we will have

U = -\frac{GM_sM_p}{r}

so we can say that energy from the fuel is converted into kinetic energy and gravitational potential energy of the satellite

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The gonads, the primary reproductive organs, are the testes in the male and the ovaries in the female. These organs are responsible for producing the sperm and ova, but they also secrete hormones and are considered to be endocrine glands.

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What stops gravity from pulling you to the center of the earth
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Answer:

electron degeneracy pressure...or in other word electro magnetic repulsion

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Light is incident along the normal to face AB of a glass prism of refractive index 1.54. Find αmax, the largest value the angle
marusya05 [52]

To solve this problem it is necessary to use the concepts related to Snell's law.

Snell's law establishes that reflection is subject to

n_1sin\theta_1 = n_2sin\theta_2

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\theta = Angle between the normal surface at the point of contact

n = Indices of refraction for corresponding media

The total internal reflection would then be given by

n_1 sin\theta_1 = n_2sin\theta_2

(1.54) sin\theta_1 = (1.33)sin(90)

sin\theta_1 = \frac{1.33}{1.54}

\theta = sin^{-1}(\frac{1.33}{1.54})

\theta = 59.72\°

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3 years ago
A pair of in-phase stereo speakers is placed side by side, 0.764 m apart. You stand directly in front of one of the speakers, 2.
Goryan [66]

Answer:

f = 2858.33 Hz

Explanation:

given,

distance between speaker (A) and the person = 2.34 m

Distance between speaker (B) and the person is AB =

            =\sqrt{(0.764)^2 + (2.34)^2}

            = 2.46 m

path difference d = BP - AP

                             = 2.46  - 2.34 m

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now,    λ = 0.12

speed of sound =  343 m/s

    f= \dfrac{c}{\lambda}

    f= \dfrac{343}{0.12}

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the lowest frequency that will produce constructive interference is equal to

f = 2858.33 Hz

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