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user100 [1]
3 years ago
12

Next one wasss:search :(

Computers and Technology
2 answers:
PolarNik [594]3 years ago
7 0
Uhmmmmmmmmm hmmmmmmmm
ExtremeBDS [4]3 years ago
4 0
Correct! but what? i’m like kinda lost here
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kodGreya [7K]
Servers <span>are the computers that store network software and shared or private user files.</span>
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4 years ago
Which of the following is an example of new and emerging classes of software?
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The answer is Smart technology :)
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When using the BinarySearch() method of an array or list type, what value is returned when the element is not found? How can we
Step2247 [10]

Answer:

When the element is not found we return -1.

Explanation:

When we use binary search we use BinarySearch() method of an array or list type when the element is found we return the index of the element if found if the element is not found we return -1.

We can decode this value since it is less than 0 and the indexing of arrays and lists starts with 0 upto the size-1.So -1 index is not present in the array or list.We have to check if the index is < 0 then the element is not present in the array or list.

for ex:-

if(index<0)

{

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3 years ago
Coupon collector is a classic statistic problem with many practical applications. The problem is to pick objects from a set of o
ahrayia [7]

Answer:

Here is the JAVA program:

public class Main {  //class name

public static void main(String[] args) {   //start of main method

//sets all boolean type variables spades, hearts diamonds and clubs to false initially

   boolean spades = false;  

   boolean hearts = false;

   boolean diamonds = false;

   boolean clubs = false;  

   String[] deck = new String[4];  //to store card sequence

   int index = 0;  //to store index position

   int NoOfPicks = 0;  //to store number of picks (picks count)

   while (!spades || !hearts || !diamonds || !clubs) {   //loop starts

       String card = printCard(getRandomCard());  //calls printCard method by passing getRandomCard method as argument to it to get the card

       NoOfPicks++;   //adds 1 to pick count

       if (card.contains("Spades") && !spades) {  //if that random card is a card of Spades and spades is not false

           deck[index++] = card;  //add that card to the index position of deck

           spades = true;  //sets spades to true

       } else if (card.contains("Hearts") && !hearts) {  //if that random card is a card of Hearts and hearts is not false

           deck[index++] = card;  

           hearts = true;   //sets hearts to true

       } else if (card.contains("Diamond") && !diamonds) {  //if that random card is a card of Diamond and diamonds is not false

           deck[index++] = card;

           diamonds = true;  //sets diamonds to true

       } else if (card.contains("Clubs") && !clubs) {  if that random card is a card of Clubs and clubs is not false

           deck[index++] = card;

           clubs = true;         }     }   //sets clubs to true

   for (int i = 0; i < deck.length; i++) {  //iterates through the deck i.e. card sequence array

       System.out.println(deck[i]);     }  //prints the card number in deck

   System.out.println("Number of picks: " + NoOfPicks);  }   //prints number of picks

public static int getRandomCard() {  //gets random card

   return (int) (Math.random() * 52); }   //generates random numbers of 52 range

public static String printCard(int cardNo) {   //displays rank number and suit

   String[] suits = { "Spades", "Hearts", "Diamonds", "Clubs", };  //array of suits

   String[] rankCards = { "Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10",

           "Jack", "Queen", "King" };   //array of rank

  int suitNo = cardNo / 13;  //divides card number by 13 and stores to suitNo

 int rankNo = cardNo % 13;   //takes modulo of card number and 13 and store it to rankNo

   return rankCards[rankNo] + " of " + suits[suitNo];  }}  //returns rankCard at rankNo index and suits at suitNo index

Explanation:

The program is explained in the comments attached with each line of code. The screenshot of the program along with its output is attached.

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3 years ago
How to write conclusion of hard disk​
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Answer:

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Explanation:

7 0
3 years ago
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