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nlexa [21]
3 years ago
7

PLZZZZ HELP ME!!!!!!!!!!! will give brainliest and 20 points why is pinball used to describe the steps in the scientific process

?
Chemistry
1 answer:
ozzi3 years ago
8 0
Well, I'm not completely sure, but, I'm going to try and help you: First, you would need to observe the machine, which, would represent the first step. Secondly, you would have to ask yourself a question, when the ball shoots out, which way are you going to hit it? Next, you'd have to hypothesize, which way the ball will come, which way will give you the most points. etc, etc. Then, you'd make a prediction based on your hypothesis, predict the direction that will give you the most points, and which way the ball will fall. Now, when the ball shoots out, you'd gave to test your prediction, then you'd see if your hypothesis was correct. Lastly, you would iterate, and, come up with new hypotheses, and, predictions, for when you play on round two, this would, also, help you get better at the game, just as, when you perform other scientific experiments, you would have a better idea on what would happen during them. I hope this helps!!!
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Explanation:

answer: uuuuh so sorry if i get wrong so basically  they will practice measuring different liquids. They will use a container called a graduated cylinder to measure liquids. Graduated cylinders have numbers on the side that help you determine the volume. Volume is measured in units called liters or fractions of liters called milliliters (ml).

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All atoms of uranium have the same
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The human body is about 9.5% carbon atoms, with a small fraction of that carbon being radioactive carbon-14. Carbon dating is a
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8 0
2 years ago
Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

7 0
3 years ago
2. Hydrogen gas at a temperature of 22.0°C that is confined in a 5.00L cylinder exerts a pressure of 4.20atm. If the gas is rele
Umnica [9.8K]

Answer: n∗R=22+273.15/4.2∗5n

P2=n∗R∗T2/V2=n∗R∗33.6+273.15/10

Explanation:

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3 years ago
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