Answer:
The 3rd image is a blue gill
Answer:
Empirical formulas can be determined from the percent composition of a compound. In order to determine its molecular formula, it is necessary to know the molar mass of the compound. Chemists use an instrument called a mass spectrometer to determine the molar mass of compounds.
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Following is the balanced <span>radioactive decay series:
</span><span>
Particle/radiations generated during the reaction are labeled in bold at end of reaction.
Care must be taken that, atomic number and atomic mass number should be balanced in each of these reactions.
1) 92 238U </span>→ <span> 90 234Th + 2 4He(</span>α particle<span>)
A = </span>90 234Th because alpha particle is emitted along with it. So atomic number of daughter element has to be 92 - 2 = 90. This corresponds to Th. <span>
2) 90 234Th </span>→<span> 91 234Pa + -1 0e (electron)
B = -1 0e i.e electron because after radioactive disintegration atomic number of daughter element (Pa) is +1 as compared to parent element (Th)
3) 91 234Pa </span>→<span> 92 234U + –1 0e (electron)
</span>C = 92 234U because electron is emitted along with it. So atomic number of daughter element has to be 91 - (-1) = 92. This corresponds to U. <span>
4) 92 234U </span>→ 90 230Th + 2 4He (α particle<span>)
</span><span>In this case, 92 234U undergoes nuclear disintegration to generate 90 230Th and alpha particle
5) 90 230Th </span>→<span> 88 226Ra + 2 4He </span>(α particle)
D = 88 226Ra because alpha particle is emitted along with it. So atomic number of daughter element has to be 90 - 2 = 88. This corresponds to Ra.
<span>6) 88 266Ra </span>→ 86 222Rn + 2 4He (α particle)
E = alpha particle because during nuclear disintegration, 88 266Ra is converted into 86 222Rn. Hence, for mass balance we have 88 - 86 = 2. It corresponds to alpha particles.
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7) 86 222Rn </span>→<span> 84 218Po + 2 4He </span>(α particle)
Again, F = alpha particle because during nuclear disintegration, 86 222Rn is converted into 84 218Rn. Hence, for mass balance we have 86 - 84 = 2. It corresponds to alpha particles.
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8) 84 218Po </span>→<span> 82 214Pb + 2 4He </span>(α particle)
G = 82 214Pb because alpha particle is emitted along with it. So atomic number of daughter element has to be 84 - 2 = 82. This corresponds to Pb.
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9) 82 214Pb </span>→<span> 83 214Bi + -1 0e (electron)
H = </span>-1 0e because after radioactive disintegration atomic number of daughter element (Bi) is +1 as compared to parent element (Pb)<span>
10) 83 214Bi </span>→<span> 84 214Po + –1 0e (electron)
I = </span>84 214Po because electron is emitted along with it. So atomic number of daughter element has to be 83 - (-1) = 84. This corresponds to Po.<span>
11) 84 214Po </span>→<span> 82 210Pb + 2 4He </span>(α particle)
J = 82 210Pb because alpha particle is emitted along with it. So atomic number of daughter element has to be 84 - 2 = 82. This corresponds to Pb.
Answer:
A physical property is an aspect of matter that can be observed or measured without changing it. A chemical property may only be observed by changing the chemical identity of a substance.
Explanation:
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A buffer has roughly equal concentrations of a weak acid and its conjugate base. The only acids in the question are HNO3 and HNO2. HNO3 is a strong acid, so it can’t be used for a buffer. The first option has HNO2 and hydrochloric acid, which won’t supply the conjugate base of HNO2, which is NO2^-1. NaCl isn’t an acid or a base, so we can eliminate that as well. That leaves us with HNO2 and NaNO2. Group 1 metals are spectators in acid-base equilibria, so we can ignore Na once it disassociates. That will give us .1M HNO2 and .1M NO2^-1, which is what we want.