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galben [10]
2 years ago
5

What is the hydrogen ion concentration of a solution with pH 5.60?

Chemistry
1 answer:
ZanzabumX [31]2 years ago
6 0

Answer:options

Explanation:

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Phosphorus reacts with oxygen to form diphosphorus pentoxide: 4 P(s) + 5 O 2(g) -> 2 P 2O 5(s) If 0.97 moles of phosphorus ar
KengaRu [80]

Answer:

0.425 moles of P₂O₅.

Explanation:

As per given balanced equation, four moles of phosphorus reacts with five moles of oxygen to give two moles of P₂O₅.

As given that the initial moles of phosphorus taken = 0.97 moles

moles of phosphorus left after reaction = 0.12 moles

moles of phosphorus reacted = 0.97-0.12 = 0.85 moles

When four moles of P reacts they give two moles of P₂O₅.

when one mole of P will react to give = \frac{2}{4}molP_{2}O_{5}

0.85 moles of P will react to give = \frac{2X0.85}{4}= 0.425molP₂O₅

6 0
3 years ago
When you have dominant allele T, recessive for t, T for tall and t for short, what will be phenotype for Tt?
Dmitry_Shevchenko [17]

Answer:

TT and Tt genotypes both expressed the tall phenotype because the T is dominant to t. Only the tt genotype expressed the short phenotype.

Explanation:

Hope this helped!

8 0
2 years ago
1. Shankar and Sameer performed an experiment to differentiate primary, secondary and tertiary amines in a laboratory.Shankar co
lesya [120]

Answer: 2) Chloroform & Caustic potash

Explanation:

The carbylamine reaction is a kind of chemical test which is done to detect primary amines in an unknown solution. It cannot detect secondary and tertiary amines.

The reaction involves the heating with up of the unknown solution with alcoholic potassium hydroxide or caustic potash and the chloroform.

In the presence of primary amine, the production of isocyanide results.

3 0
2 years ago
What are the half-reactions for a galvanic cell with aluminum and gold electrodes?
pashok25 [27]

Answer:B is right

Explanation: Al loses electrons and is oxidised, Au gains electron. And is reduced

4 0
2 years ago
When copper oxide is reacted with sulfuric acid, the acid is often gently heated. This is done in order to:
pav-90 [236]
Copper oxide(solid) + Sulphuric Acid (aqueous)-> Copper Sulphate (aqueous)+ Water(liquid)

In equation form:

CuO +H2SO4 -> CuSO4 + H2O

The colour change you will see is black to blue as Copper oxide is usually found as a black powder. Upon the reaction with sulphuric acid it will change to a cyan blue.

If you heat the made solution of copper sulphate, the water will evaporate and you will be left with white anhydrous copper sulphate crystals.
7 0
2 years ago
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