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3 years ago

A block is pulled 0.90 m to the right in 3.75 s.

Chemistry

1 answer:

VLD [36.1K]3 years ago

4 0

Answer:

0.36 m/s

Explanation:

im in 8th grade in honors science and i think, since u have distance and time you have to divide distance by time

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An alkene adds hydrogen in the presence of a catalyst to give 3,4-dimethylhexane. Ozonolysis of the alkene followed by treatment

slamgirl [31]

The structure of alkene is given below in the image.

Alkenes are described as both branched or unbranched hydrocarbons that possess at least one carbon-carbon double bond (CC) and feature a popular system of CnH2n [1].

Alkanes are organic compounds that encompass single-bonded carbon and hydrogen atoms. The formulation for Alkanes is CnH2n+2, subdivided into 3 companies – chain alkanes, cycloalkanes, and branched alkanes.

The geometry around each carbon atom is based totally on a trigonal planar shape, due to the fact, that each carbon has three electrons around it. This must make the angle of each bond one hundred twenty.

Learn more about Alkanes here: brainly.com/question/17040500

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2 years ago

When you blow dry your hair is it physical or chemical change

viva [34]

When you blow dry your hair you will get a physical change

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4 years ago

Read 2 more answers

socratic For the following reaction, 25.6 grams of hydrochloric acid are allowed to react with 52.4 grams of barium hydroxide .

TEA [102]

Answer:

63.7g BaCl₂

Explanation:

Based on the chemical reaction:

2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

2 moles of HCl reacts per mole of barium hydroxide

To solve this question, we need to convert the moles of each reactant to moles and, using the chemical reaction, find limiting reactant as follows:

Moles Ba(OH)₂ - Molar mass: 171.34g/mol-

52.4g Ba(OH)₂ * (1mol / 171.34g) = 0.306 moles Ba(OH)₂

Moles HCl - Molar mass: 36.46g/mol-

25.6g HCl * (1mol / 36.46g) = 0.702 moles HCl

For a complete reaction of 0.702 moles HCl are required:

0.702 moles HCl * (1mol Ba(OH)₂ / 2mol HCl) = 0.351 moles of Ba(OH)₂

As there are just 0.306 moles, limiting reactant is Ba(OH)₂

That means the maximum amount of BaCl₂ produced is:

0.306 moles Ba(OH)₂ * (1mol BaCl₂ / 1 mol Ba(OH)₂) = 0.306 moles BaCl₂

In mass -Molar mass BaCl₂: 208.23g/mol-

0.306 moles BaCl₂ * (208.23g / mol) = 63.7g BaCl₂

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3 years ago

Draw the major product(s) of nitration of benzenesulfonic acid. you do not have to consider stereochemistry. you do not have to

emmasim [6.3K]

As we know Benzene undergo Electrophilic Substitution Reactions. In case of substituted Benzene the incoming Electrophile is substituted either at Orto , Para position or Meta position. If the substituent is Electron Withdrawing in Nature then the Electrophile will go to meta position. When the substituent id Electron Donating in Nature then the incoming electrophile will be directed to ortho and para position.

In Benzenesulfonic Acid the substituent is Sulfonate (-SO₃H), it has a strong electron withdrawing effect. So on Nitration the Nitro group will be oriented to meta position and 3-nitrobenzenesulfonic acid is formed. On further Nitration 3-nitrobenzenesulfonic acid will be convert to 3,5-dinitrobenzenesulfonic acid because both Sulfonate and Nitrate groups are meta directing.

8 0

3 years ago

Upon landing, the 90.7 kg carbon fiber brakes of an airliner heat up 312∘C, producing heat. As the brakes start to cool back to

Crank

Given,

Mass of carbon fiber brakes = 90.7 kg = 90.7 x 1000 = 90700 g

Mass of the rubber tires = 123 kg = 123 x 1000 = 123000

Specific heat of carbon fiber = 1.400Jg∘C

As all the heat is transferred from the carbon fiber brakes to the rubber tires, the heat lost by the carbon fiber brakes is equal to the heat gained by the rubber tires.

So the temperature change of carbon fiber brakes, delta T = 172∘C

And the temperature change of rubber tires, delta T = 172∘C

The formula used for heat is,

Q = m s delta T

where Q is heat, m is mass, s is specific heat, and delta T is the temperature change

We know,

Heat lost by the carbon fiber brakes = Heat gained by the rubber tires

90700 g x 1.400Jg∘C x 172∘C = 123000 g x s x 172∘C

or, 90700 g x 1.400Jg∘C = 123000 g x s

or, s = (90700 g x 1.400Jg∘C) / 123000 g

or, s = 1.03236

Therefore, the specific heat of rubber tires is 1.03236 Jg∘C

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3 years ago

Read 2 more answers