F is continuous every-where. But it is not differentiable at two points. Note <span>it is not differentiable at </span><span>x = 0</span><span> and </span><span>x = 1! I mean just consider </span>f(x)= ∣x∣+∣x − 1∣
If you need me to expand let me explain it a bit more.
If you define a function f(x) so that f(x) = |x| for x<0. f(x) = sinx for 0 ≤ x < 22/7, We have f(x) = |x - 22/7| for x ≥ 22/7 then we can say this function is continuous however it will still have two points that are not differentiable. This would be for |x|
Answer:
C. 5 weeks.
Step-by-step explanation:
In this question we have a random variable that is equal to the sum of two normal-distributed random variables.
If we have two random variables X and Y, both normally distributed, the sum will have this properties:
To calculate the expected weeks that the donation exceeds $120, first we can calculate the probability of S>120:
The expected weeks can be calculated as the product of the number of weeks in the year (52) and this probability:
The nearest answer is C. 5 weeks.
X = 14
you set all the sides equal to 52 and combine like terms.
52=2x-7+x+3+x
52=4x-4
add 4 to each side
52+4=4x-4+4
56=4x
divide each side by 4
56/4=4x/4
14=x
Answer:
11/12 = 22/24
1/8 = 3/24
Step-by-step explanation:
Rewriting input as fractions if necessary:
11/12, 1/8
For the denominators (12, 8) the least common multiple (LCM) is 24.
LCM(12, 8)
Therefore, the least common denominator (LCD) is 24.
Answer:
(1,-7)
Step-by-step explanation:
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