Calculate the number of moles of sulfuric acid in 0.49 g of sulfuric acid, H2SO4

vlabodo [156]

Answer:

Commonly from a guys perspective and where you live it can be 50/50. In the city life, your gal or lad will likely leave you for another boy or girl since there are more to choose from or rather date.

6 0

2 years ago

Read 2 more answers

6 moles of potassium permanganate (KMnO4) are dissolved in enough water to make a 3M solution. What is the volume of the solutio

Yanka [14]

Answer:

2000 mL

Explanation:

Given data:

Number of moles KMnO₄ = 6 mol

Molarity of solution = 3M

Volume of solution in mL = ?

Solution:

Formula:

Molarity = number of moles of solute / volume of solution in L

3 M = 6 mol / volume of solution in L

volume of solution in L = 6 mol/ 3 M

volume of solution in L = 2 L

Now we convert the L into mL:

1 L = 1000 mL

2 L × 1000 mL / 1 L

2000 mL

7 0

2 years ago

The electrolysis of water forms H2 and O2. 2H2O 2H2 + O2 What is the percent yield of O2 if 10.2 g of O2 is produced from the de

BigorU [14]

Answer: The percent yield of oxygen gas is 67.53 %.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of water = 17.0 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{17.0g}{18g/mol}=0.944mol$

For the given chemical equation:

$2H_2O\rightarrow 2H_2+O_2$

By Stoichiometry of the reaction:

2 moles of water produces 1 mole of oxygen gas

So, 0.944 moles of water will produce = $\frac{1}{2}\times 0.944=0.472moles$ of oxygen gas

Now, calculating the mass of oxygen gas from equation 1, we get:

Molar mass of oxygen gas = 32 g/mol

Moles of oxygen gas = 0.472 moles

Putting values in equation 1, we get:

$0.472mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.472mol\times 32g/mol)=15.104g$

To calculate the percentage yield of oxygen gas, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of oxygen gas = 10.2 g

Theoretical yield of oxygen gas = 15.104 g

Putting values in above equation, we get:

$\%\text{ yield of oxygen gas}=\frac{10.2g}{15.104g}\times 100\\\\\% \text{yield of oxygen gas}=67.53\%$

Hence, the percent yield of oxygen gas is 67.53 %.

7 0

2 years ago

Read 2 more answers

How many grams of calcium are required to react with 12 grams of oxygen to form caO

MaRussiya [10]

30.58 grans of Calcium ...

5 0

3 years ago

Explain how it is possible that a problem with hormones and feedback led to Anna Garcia’s untimely death.

nata0808 [166]

Because Anna was diabetic, if the hormones in her body could not effectively perform feedback then she could have had extremely low or high blood sugar which could ultimately cause her to become unconscious or deceased.

8 0

2 years ago