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Kaylis [27]
3 years ago
12

Tìm tọa độ của vecto u=(3;x;y) tromg cơ sở {(0;1;-1), (1;2;-2); (2;-1;2)}​

Mathematics
1 answer:
fgiga [73]3 years ago
4 0

Answer:

baams mays ra

Step-by-step explanation:

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URGENT I NEED THIS DONE PLEASE ILL GIVE THE FIRST ANSWER BRAINLIEST Charles begins finding the volume of a trapezoidal prism usi
ss7ja [257]

Answer:

2x3 + 6x2

Step-by-step explanation:

8 0
3 years ago
Write an equation of the line that passes through (0,4) and (1,2
Aleks04 [339]

Answer:

y = mx + b

y = -2x + 4

Step-by-step explanation:

m = 2 - 4 / 1 - 0 = -2 / 1 = -2

m (slope) = -2

y = mx + b      (0,4)

4 = -2x + 0

<u>-0         - 0</u>

<u>4</u> = <u>-2x</u>

-2   -2

-2 = x

Equation:  y = mx + b

y = -2x + 4

Hope that helps!! Please give me brainliest!!

7 0
3 years ago
Two cities are building bicycle paths. Charles City has built 5km of bicycle paths by the end of the first month, and the total
sergey [27]

Answer:

Month 4

Step-by-step explanation:

To solve this problem we must propose an equation that models the number of kilometers of bicycle trails made monthly in Charles City and in Tinsel Town

<em>For Charles City </em>we know that the number of kilometers built in the first month is 5, and it doubles every month. Then we have an exponential equation, in base 2, whose initial value is 5.

This equation has the following form:

y = C_1 (2^{x-1})

Where:

C_1 is the number of kilometers built in month 1

x is the number of months: {1, 2, 3, 4, 5 ... x}

x = 1 represents month 1.

So:

Charles\ City\ (km) = 5(2^{x-1})

<em>For Tinsel Town</em> we know that the number of kilometers built in the first month is 21 and increases at a fixed rate of 5 kilometers per month. This can be modeled by a linear equation.

Tinsel\ Town\ (km) = 21 + 5(x-1)

Where x is the number of months. x: {1, 2, 3, 4, 5 ...}

We want to know at the end of what month the total length of the cycle lanes in Charles City first exceeds the length in Tinsel Town

Then we equal both equations and clear x.

5 (2^{x-1}) = 21 + 5(x-1)\\\\5 (2^{x-1}) - (21 + 5(x-1)) = 0

Clearing x from this equation is very difficult, so to find x, we iterate until we get the value of x that causes the equation to approach 0.

For x = 3

5(2^{3-1}) - (21 +5(3-1)) = 0\\\\20- 31= -11

For x = 4

5(2^{4-1}) - (21 +5(4-1)) = 0\\\\40 - 36 = 4

<em>The value must be between x = 3 and x = 4</em>

For x = 3.8

5 (2^{3.8-1}) - (21 +5(3.8-1)) = 0\\\\34.82 - 35 = 0.18

Then x ≈ 3.8 months.

Finally we have that By the end of the fourth month the total length of the cycle lanes in Charles City exceeds the length in Tinsel Town

6 0
4 years ago
W= x/y-x solve for x
svetoff [14.1K]

Answer: w=−xy+x/y

Step-by-step explanation:

Let's solve for w.

w=

x

y

−x

Step 1: Multiply both sides by y.

wy=−xy+x

Step 2: Divide both sides by y.

wy

y

=

−xy+x

y

w=

−xy+x

y

3 0
3 years ago
The table in the lesson shows the number of sets of twins, triplets, quadruplets, and quintuplets registered at a twin conventio
Korolek [52]

Answer:

  5494

Step-by-step explanation:

Assuming all members of each set registered, the total number is ...

  2(2697) +3(29) +4(2) +5(1) = 5494

__

Since you're concerned with order of operations, perhaps you want to see the working out.

  = 5394 + 87 +8 +5 . . . . perform all the multiplications

  = 5481 +8 +5 . . . . . . . . . perform addition left to right

  = 5489 +5

  = 5494

8 0
3 years ago
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