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Flauer [41]
3 years ago
8

Name the following alkane molecule:

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
5 0

Answer:

6- bromo- 2-chlorodecane

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How much heat is needed to melt 100.0 grams of ice that is already at 0°C?
Jet001 [13]

Taking into account the definition of calorimetry and latent heat, the heat needed to melt 100.0 grams of ice that is already at 0°C is 33,400 J (option A).

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

In this case, the heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

<h3>Heat needed to melt ice</h3>

In this case, you have to melt the ice into liquid water.Being the specific heat of melting of ice is 334 J/g, the heat needed to melt 100 grams of ice is calculated as:

Q= 100 grams× 334 J/g

Solving:

<u><em>Q= 33,400 J</em></u>

In summary, the heat needed to melt 100.0 grams of ice that is already at 0°C is 33,400 J (option A).

Learn more about calorimetry:

brainly.com/question/15224761

#SPJ1

4 0
1 year ago
What is the number of moles of glucose C6H12O6 in a 134g sample?
Shkiper50 [21]
The question is simply asking to convert from units of mass to units of moles. To do this, a conversion factor is needed. For this case, we use the molar mass of glucose which is equal to 180.18 g/mol. We do as follows:

134 g C6H12O6 ( 1 mol / 180.18 g ) = 0.744 mol <span>C6H12O6</span>
5 0
4 years ago
Calculate the number atoms in a 92.8 mg of Si
Step2247 [10]

Answer: the answer is that stop using brainly for your answer dumb kid

Explanation:

dwcwcwcwcwce

8 0
4 years ago
A sealed, expandable container is initially at 2.000 L and 25°C. To what temperature must it be changed to have a volume of 6.00
balandron [24]

Answer:

The new temperature is 894 K or 621 °C

Explanation:

Step 1: Data given

Initial volume of the container = 2.000L

Initial temperature = 25.0 °C = 298 K

Volume increased to 6.00 L

Step 2: Calculate the new temperature

V1/T1 = V2/T2

⇒with V1 = the initial volume = 2.00L

⇒with T1 = the initial temperature = 25 °C = 298 K

⇒with V2 = the increased volume 6.00 L

⇒with T2 = the new temperature

2.00 L / 298 K = 6.00 L / T2

T2 = 894 K = 621 °C

The new temperature is 894 K or 621 °C

4 0
4 years ago
Is it the Esophagus , Small intestine , Mouth or Stomach ?
Alenkasestr [34]

Answer:

The esophagus

7 0
3 years ago
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