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3 years ago

12

How many number of oxygen molecules are required to produce 0.22 g of CO2 according to the reaction?

1 answer:

zmey [24]3 years ago

3 0

The number of moles for co2=mass(g)/molar mass
n=.22/44=.005 mole of CO2
from the equation we see the relationship between the moles of co2 and O2 and we find that they have the same number of moles
So we need .005mole of O2
Multiple the number of moles with avogadro’s number to know the number of O2molecules
.005x6.022 x10^23

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3 years ago

A mixture of He, Ne, and Ar gases at a particular temperature has partial pressures of 0.75 atm He, 0.30 atm Ne, and 0.62 atm Ar

inessss [21]

Answer:

The order of mole fraction in increasing order will be:

$\chi_{Ne}$

Explanation:

Relation between mole fraction and partial pressure of the component is given as:

$p_i=P\times \chi_i$

Where :P = Total pressure of the mixture

$p_i$ = partial pressure of the i component

$\chi_i$ = Mole fraction of the i component

We have :

Partial pressure of the helium gas , $p_{He}$ = 0.75 atm

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Partial pressure of the argon gas , $p_{Ar}$ = 0.62 atm

As we can see that from the above equation, that partial pressure and mole fraction are directly linked to each other.

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So, the order of partial pressure from lowest to highest is:

$p{Ne}$

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4 years ago

Container A holds 767 mL of an ideal gas at 2.80 atm. Container B holds 154 mL of a different ideal gas at 4.50 atm.

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Answer:

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2 years ago

Identify the phrases that generally apply to molecular compounds a contain metals and nonmetals

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4 years ago

Read 2 more answers

A plate moves 200 m in 10,000 years. What is its rate in cm/year?

Varvara68 [4.7K]

Answer:

The answer is

<h2>2 cm/year</h2>

Explanation:

To find the rate in cm/year we must first convert 200 m into cm

1 m = 100 cm

if 1 m = 100 cm

Then 200 m = 200 × 100 = 20 ,000 cm

So the rate is

<h2> $\frac{20000}{10000}$ </h2>

<u>Reduce the fraction with 10,000</u>

We have the final answer as

<h3>2 cm/year</h3>

Hope this helps you

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3 years ago