Answer:
i think turning on a flashlight or light bulb might be a good example
Explanation:
<u>Answer:</u> The correct answer is Option 2.
<u>Explanation:</u>
Radioactive substances are unstable in nature and tend to get stable by some nuclear reactions.
Nuclear reaction are the reactions which changes the nucleus of an atom. There are two nuclear reactions: Nuclear fission and Nuclear fusion.
These two processes can make a radioactive sample can convert it into a non-radioactive sample.
Nuclear fission reactions: In these reactions a larger nuclei (parent nuclei) splits into two or more stable daughter nuclei.
Nuclear fusion reactions: When two or more smaller nuclei combine to form one larger nuclei, these reactions takes place.
In the question, it is asked the characteristic of a non-radioactive daughter isotope after it is formed from a parent isotope. The parent isotope is undergoing nuclear fission reaction and is forming a stable nucleus.
Hence, the correct answer is Option 2.
First blank -Same
Second blank-Neutral
Explanation:
(1) When a proton is converted into neutron then the positron emission takes place as follows.
![^{1}_{1}p \rightarrow ^{1}_{0}n + ^{0}_{+1}e](https://tex.z-dn.net/?f=%5E%7B1%7D_%7B1%7Dp%20%5Crightarrow%20%5E%7B1%7D_%7B0%7Dn%20%2B%20%5E%7B0%7D_%7B%2B1%7De)
A positron is represented by the symbol
. Therefore, when a positron emission occurs then the resultant nuclei atomic number decreases by a unit mass.
General equation representing positron emission is as follows.
![^{M}_{Z}A \rightarrow ^{M}_{Z-1}B + ^{0}_{+1}e](https://tex.z-dn.net/?f=%5E%7BM%7D_%7BZ%7DA%20%5Crightarrow%20%5E%7BM%7D_%7BZ-1%7DB%20%2B%20%5E%7B0%7D_%7B%2B1%7De)
Hence, Fluorine-18 decays by positron emission as follows.
![^{18}_{9}F \rightarrow ^{18}_{8}O + ^{0}_{+1}e](https://tex.z-dn.net/?f=%5E%7B18%7D_%7B9%7DF%20%5Crightarrow%20%5E%7B18%7D_%7B8%7DO%20%2B%20%5E%7B0%7D_%7B%2B1%7De)
Therefore, when 18F undergoes positron emission, the product nucleus is,
.
(2) Expression for the half-life of a
isotope is as follows.
![t_{\frac{1}{2}} = \frac{0.693}{\lambda}](https://tex.z-dn.net/?f=t_%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%3D%20%5Cfrac%7B0.693%7D%7B%5Clambda%7D)
Initial activity, (
) = 4.00 millicuries
Activity after 95% = ![4.00 - 4.00 \times \frac{95}{100}](https://tex.z-dn.net/?f=4.00%20-%204.00%20%5Ctimes%20%5Cfrac%7B95%7D%7B100%7D)
= 0.20 millicuries
![\lambda = \frac{2.303}{t} log \frac{[N]_{o}}{[N]_{t}}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B2.303%7D%7Bt%7D%20log%20%5Cfrac%7B%5BN%5D_%7Bo%7D%7D%7B%5BN%5D_%7Bt%7D%7D)
t = 7.912 hrs
Thus, we can conclude that it will take 7.91 hrs for 95% of the 18F to decay.
Answer:
a. Ethanol.
b. 4.21 mL H2O.
c. 87.8%
Explanation:
Hello,
- For the limiting reactant, the available amount of ethanol is less than the ideal amount of ethanol that would react with the given amount of oxygen, that's why it is the limiting one.
- You will find the calculations in the attached picture; take into account that the molecular mass of water is 18 g/mol and ethanol 46 g/mol.
- The percent yield is allowed to be computed in terms of volume as well, because the relationships are conserved.
Best regards!