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Mazyrski [523]
4 years ago
8

Adults should also do muscle-strengthening activities that involve all major muscle groups, performed on _____ or more days per

week.
A 7
B 2
C 5
D 4
Physics
1 answer:
Novay_Z [31]4 years ago
8 0
The answer is B. 2 
Hope I helped!
Let me know if you need anything else! 
~ Zoe
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When an object is moving with uniform circular motion, the centripetal acceleration of the object a. is circular. b. is perpendi
never [62]
Hi Pupil Here's Your answer :::


➡➡➡➡➡➡➡➡➡➡➡➡➡


When an object is moving with uniform circular motion, the centripetal acceleration of the object \textbf{is\:Zero}.


Because the body is moving with a uniform velocity and hence, there might not be any acceleration due to it.


⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅



Hope this helps .......
5 0
3 years ago
At what temperature will silver have a resistivity that is two times the resistivity of iron at room temperature? (Assume room t
emmasim [6.3K]

Answer:

The temperature of silver at this given resistivity is 2971.1 ⁰C

Explanation:

The resistivity of silver is calculated as follows;

R_t = R_o[1 + \alpha(T-T_o)]\\\\

where;

Rt is the resistivity of silver at the given temperature

Ro is the resistivity of silver at room temperature

α is the temperature coefficient of resistance

To is the room temperature

T is the temperature at which the resistivity of silver will be two times the resistivity of iron at room temperature

R_t = R_o[1 + \alpha(T-T_o)]\\\\\R_t = 1.59*10^{-8}[1 + 0.0038(T-20)]

Resistivity of iron at room temperature = 9.71 x 10⁻⁸ ohm.m

When silver's resistivity becomes 2 times the resistivity of iron, we will have the following equations;

R_t,_{silver} = 2R_o,_{iron}\\\\1.59*10^{-8}[1 + 0.0038(T-20)] =(2 *9.71*10^{-8})\\\\\ \ (divide \ through \ by \ 1.59*10^{-8})\\\\1 + 0.0038(T-20) = 12.214\\\\1 + 0.0038T - 0.076 = 12.214\\\\0.0038T +0.924 = 12.214\\\\0.0038T  = 12.214 - 0.924\\\\0.0038T = 11.29\\\\T = \frac{11.29}{0.0038} \\\\T = 2971.1 \ ^0C

Therefore, the temperature of silver at this given resistivity is 2971.1 ⁰C

8 0
4 years ago
If feathers have a density of 0.500 lbs/ft^3, what volume in ft^3 will 8.0 lbs of feathers occupy?
OleMash [197]

Answer:

<em>The volume of the feathers in ft³ = 16 ft³</em>

Explanation:

Density: This can be defined as the ratio of mass of a body to the corresponding volume of that body. The S.I unit of Density is kg/m³

Mathematically it can be expressed as,

D = m/v ................................... Equation 1

making v the subject of the equation above,

v = m/D ............................. Equation 2

Where D = Density of the feathers, m = mass of the feathers, v = volume of the feathers.

Given: D = 0.50 lbs/ft³, m = 8.0 lbs.

Substituting into equation 2

v = 8/0.5

v = 16 ft³

<em>Thus the volume of the feathers in ft³ = 16 ft³</em>

3 0
3 years ago
Derive a relation between time period anf frequency of a wave
Elza [17]

Answer:

The relation between frequency and time period is given by:

f = 1/T

Explanation:

In a wave motion, the particle move about the mean position with the passage of time. The particles rise to reach the highest point which is crest, and similarly falls to reach the lowest point which is trough. The cycle keeps on repeating.

The time period of the wave can be defined as the time taken to complete one such cycle. Time period is given by:

T = 2π/ω

Frequency can be defined as the number of cycles completed in unit time, which can be taken as the inverse of time period. frequency is given by

f = ω/2π

or

f = 1/T

8 0
4 years ago
A person drives a car around a circular road with a constant speed of 20 m/s. The
ale4655 [162]

Answer:

16 m/s^2

Explanation:

acceleration tangential = (v^2)/r

a=400/25

a=16 m/s^2

Side note: next time, be more specific when asking about acceleration in circular motion. There's more than one type! Example:

angular acceleration=acceleration tangential/r

angular acc.=16/25

angular acc.=0.64 rad/s^2

5 0
3 years ago
Read 2 more answers
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