The answer is variant C because every living organism needs water to survive. A human can live without water only 6 days, after that period the most important organs start to shut down because of the lack of water.
A fundamental niche can be defined as the range of environmental conditions in which each of the species survives. The realized niche can be termed as the range of environmental conditions in which a species is really found.
Without friction, the amount of work only depends on the final height,
and is not affected by the route used to get there.
If the ramp has no friction, then it has no effect on the total amount
of work done. The work to lift the load straight up is the same.
If the ramp has some friction, then it takes more work to use the ramp
than to lift the load straight up. Then the work to lift the load straight up
would be less than when the ramp is used.
Answer:
30 miliAmps
Explanation:
Step 1:
Obtaining an expression to solve the question. This is illustrated below:
From ohm's law,
V = IR
Were:
V is the voltage.
I is the current.
R is resistance.
From the question given, we were told that the resistance is constant. Therefore the above equation can be written as shown below:
V = IR
V/I = constant
V1/I1 = V2/I2
V1 is initial voltage.
V2 final voltage.
I1 is initial current.
I2 final current.
Step 2:
Data obtained from the question. This include the following:
Initial voltage (V1) = V
Initial current (I1) = 60 miliAmps
Final voltage (V2) = one-half of the original voltage = 1/2V = V/2
Final current (I2) =..?
Step 3:
Determination of the new current. This can be obtained as follow:
V1/I1 = V2/I2
V/60 = (V/2) / I2
Cross multiply to express in linear form
V x I2 = V/2 x 60
V x I2 = V x 30
Divide both side by V
I2 = (V x 30)/V
I2 = 30mA.
Therefore, the new current is 30miliAmps
Answer:
Explanation:
Ball rises and falls in equal periods. Because it goes by same speeds and same route. Therefore t_{rise} = t_{fall} =2.5 s
In free fall and vertical throw movement: x= (1/2).a.t^{2}
Here, we can find the height of the ball
x= (1/2).5.(2.5^{2}) = 15.625 m
From the attaches V-t graphics, x=V.t/2
15.624=V.(2.5)/2
V=12.5 m/s
