Question

The formation of condensation on a glass of ice water causes the ice to melt faster than it would otherwise. If 8.55 g of condensation forms on a glass containing both water and 244 g of ice, how many grams of the ice will melt as a result? Assume no other heat transfer occurs. The heat of fusion and vaporization is 79.8 amd 580 kcal/kg, respectively.

Answer 1

Answer:

m = 62.14 g

Explanation:

Energy used to melt the ice is the energy released by the condensation of the water forms on the glass

so here we have

energy for the condensation of water is given as

let mass of water condensed = m

$E = m_1 L_f$

now the energy of vaporization is given as

$E = m_2 L_v$

here we know that

$L_f = 79.8 kCal/kg$

$L_v = 580 k Cal/kg$

Now we have

$8.55 \times 580 = m \times 79.8$

$m = 62.14 g$