Answer:
Flow Rate = 80 m^3 /hours (Rounded to the nearest whole number)
Explanation:
Given
- Hf = head loss
- f = friction factor
- L = Length of the pipe = 360 m
- V = Flow velocity, m/s
- D = Pipe diameter = 0.12 m
- g = Gravitational acceleration, m/s^2
- Re = Reynolds's Number
- rho = Density =998 kg/m^3
- μ = Viscosity = 0.001 kg/m-s
- Z = Elevation Difference = 60 m
Calculations
Moody friction loss in the pipe = Hf = (f*L*V^2)/(2*D*g)
The energy equation for this system will be,
Hp = Z + Hf
The other three equations to solve the above equations are:
Re = (rho*V*D)/ μ
Flow Rate, Q = V*(pi/4)*D^2
Power = 15000 W = rho*g*Q*Hp
1/f^0.5 = 2*log ((Re*f^0.5)/2.51)
We can iterate the 5 equations to find f and solve them to find the values of:
Re = 235000
f = 0.015
V = 1.97 m/s
And use them to find the flow rate,
Q = V*(pi/4)*D^2
Q = (1.97)*(pi/4)*(0.12)^2 = 0.022 m^3/s = 80 m^3 /hours
Answer:
C) 5ML^2
Explanation:
2 Spheres of mass M
Bug's mass 3M
Rod length 2L, radius L
Find Rotational Inertia I
I=Σmr^2
I=(3M+M+M)L^2
I=5ML^2
A. 4x the force is the correct answer
Answer:
(a) 10 nm
(b) 1 Hz
(c) 20 V/m
Explanation
The equation of a progressive wave is given by:
y = Asin(kx ± ωt)
where;
A is the amplitude of the wave in meters
y(x,t) is the displacement in meters
k = 2π/λ is the propagation constant
ω = 2πf is the angular frequency in radian per seconds
The equation now becomes;
y = Asin((2πx)/λ ± 2πft)
(a) Comparing Ey= (20 V/m)sin((6.28x10⁸)x -2πft) with the general equation
(2πx)/λ = 6.28 × 10⁸
λ = 2π / 6.28 × 10⁸
λ = 1.0 × 10⁻⁸ m
λ = 10 × 10⁻⁹ m
λ = 10 nm
(b) Comparing Ey= (20 V/m)sin((6.28x10⁸)x -2πft) with the general equation
2πft = 2πft
f = 1 Hz
(c) Comparing Ey= (20 V/m)sin((6.28x10⁸)x -2πft) with the general equation
A = 20 V/m
Answer:
PE=0
Explanation:
If the tank is on the ground, there is 0 height which means the equation of PE=mh will be PE=12543(0)=0, hope this helps!