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koban [17]
3 years ago
8

The bohr shift on the oxygen-hemoglobin dissociation curve is produced by changes in

Physics
1 answer:
Alisiya [41]3 years ago
7 0

Answer:

THE BOHR SHIFT ON THE OXYGEN-HEMOGLOBIN DISSOCIATION CURVE IS PRODUCED BY CHANGES IN THE CONCENTRATION OF CARBON IV OXIDE.

Explanation:

The oxygen-hemoglobin dissociation curve shows the relationship between the saturated hemoglobin concentration and oxygen. It shows how the blood hold on to and releases oxygen. The Bohr shift can occur as a result of changes in concentration of carbon iv oxide and other factors such as acidity or pH, 2,3-bisphosphoglycerate, exercise, also temperature of the body. These factors contributes to the right or left shift on the curve. Carbon iv oxide prevents the binding of oxygen to the hemoglobin. The is because hemoglobin has the same binding site for both oxygen and carbon iv oxide. Carbon iv oxide increase also leads to a change in the pH of the blood through the formation of bicarbonate ion. Bicarbonate ion formation causes reduced acidity and therefore lead a shift in the dissociation curve for more of the carbon iv oxide to be excreted as hemoglobin's affinity for oxygen reduces. And when the concentration of carbon iv oxide is low in the plasma, acidity increases and this provides more affinity for oxygen by the hemoglobin.

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lesantik [10]

Answer:

Height as seen by the professor = 38.2 m

Explanation:

Angle of throw = θ = 69°

Velocity of throw = v

X component of velocity = v₁ = v cos 69 = 0.3584 v m/s

Vertical component of the velocity = v₂ =  v sin 69 = 0.9336 v m/s

v₂ / v₁ = tan 69 = 2.605

v₂ = 2.605 v₁.

Professor sees as if the x component of velocity =0

v (as seen by professor) + v'  = 0

=> v  as seen by professor = -v' = -10.5 m/s

This shows that y component of the ball's velocity is 2.605 times its x component of velocity.

with respect to the professor, there is only y component of velocity.

v₂' =v₂ = 2.605 ( -10.5) = 27.4 m/s.

Height as seen by the professor = (27.4)² / 2(9.8) = 38.2 m

4 0
3 years ago
An object originally at rest, is accelerated uniformly along a straight line to a speed of 8m/s in 2s. What is the acceleration
Anna11 [10]

Answer:

4m/s²

Explanation:

Initial velocity (u) = 0 m/s

Final velocity (v) = 8 m/s

Time taken (t) = 2 sec

Acceleration (a) = ?

We know

a  =  \frac{v - u}{t}  \\  =  \frac{8 - 0}{2} \\  =  \frac{8}{2}  \\  = 4 \: m |s ^{2}

Hope it will help :)

3 0
3 years ago
An airplane starts from rest and accelerates at a constant 3.00 m/s2
katrin2010 [14]

Answer:600 m

Explanation:

6 0
3 years ago
Suppose you have two small pith balls that are 5.5 cm apart and have equal charges of -29 nc?
Alina [70]
The question is missing, however, I guess the problem is asking for the value of the force acting between the two balls.

The Coulomb force between the two balls is:
F= k_e \frac{ q_1 q_2}{r^2}
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Substituting these numbers into the equation, we get
F=2.5~10^{-3}~N

The force is repulsive, because the charges have same sign and so they repel each other.
6 0
3 years ago
Calculate the electrical energy expended in a device across which the circuit voltage drops by 50 volts in moving a charge of 6
solmaris [256]
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5 0
4 years ago
Read 2 more answers
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