Most enzymes' optimum pH is neutral or close to neutral, like amylase found in saliva, which has an optimal pH = 6.8. Some enzymes prefer a more drastic pH, like pepsin, which can have an optimum pH of 1.7 to 2. Sometimes enzyme pH optima depends on where the enzyme is found.
Answer:
N = 187.55
Explanation:
Here you just need to replace the terms and clear the equation.
You already know that,
- First capture: 25 prairie dogs.
- First marked animals: 25 (the whole first capture)
You let these animals leave and then you made another capture.
- Second capture: 135 prairie dogs
- Already Marked animals: 18 (these 18 dogs were caught in the first capture and marked before releasing them)
To know the size of the prairie dogs population you just need to use the following equation and clear N, which is the value that you are looking for.
Number of individual marked in first catch/Total population size, N = Number of individual marked in 2nd catch / Total number of 2nd catch
- Number of individual marked in first catch = 25 dogs
- Total population size, N = this is what we want to know
- Number of individual marked in 2nd catch = 18 dogs
- Total number of 2nd catch = 135 dogs
So now, we need to replace terms
25 / N = 18 / 135
25 / N = 0.1333
N = 25 / 0.1333
N = 187.55
Answer:
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Explanation:
Answer:
When the pKa is 6.0, we can determine the fraction of protonated H is by:
pH = pKa + log [A]/[HA]
Where
A = Deprotonated imidazole side
HA = Protonated side
Given, pH = 5.0
5 = 6 + log [A]/[HA]
log [A]/[HA] = -1 (take antilog of both side)
[A]/[HA] = 0.1
The ratio of the deprotonated imidazole side chain to the protonated side chain at pH 5.0 = 0.1
Given, pH = 7.5
7.5 = 6 + log [A]/[HA]
log [A]/[HA] = 1.5 (take antilog of both sides)
[A]/[HA] = 31.62
The ratio of the deprotonated imidazole side chain to the protonated side chain at pH 5.0 = 31.62
