Cart 1 of mass 3.0 kg moving to the right at 2 m/s and collides with a Cart 2 of mass 2.0 kg moving to the left at
1 answer:
Answer:
V = -0.4 m/s
Explanation:
Given that,
Mass of cart 1, m₁ = 3 kg
Speed of cart 1, v₁ = 2 m/s
Mass of cart 2, m₂ = 2 kg
Speed of cart 2, v₂ = -4 m/s (left)
aWe need to find the velocity of the carts after the collision if they stick together. Let the common speed be V. Using the law of conservation of momentum to find it such that,
Put all the values,
So, the velocity of the carts after the collision is equal to 0.4 m/s to the left.
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Answer:
the banking angle of the road is 24.2⁰
Explanation:
Given;
speed of the vehicles considered, v = 75 mi/h
Speed in m/s ⇒ 1 mi/h --------> 0.44704 m/s
75 mi/h --------> ?
= 75 x 0.44704 m/s = 33.528 m/s
radius of the curve, r = 255 m
The banking angle of the road is calculated as;
Therefore, the banking angle of the road is 24.2⁰
Answer:
Initial speed of the spaceship 1, v = 2 m/s
Explanation:
Given that :
Mass of spaceship 1 and 2 that have equal mass are 300 kg
Initial momentum of the spaceship 1 is 600 kg-m/s
To find :
We need to find the initial momentum of spaceship 1.
Solve :
The momentum of an object is equal to the product of mass and its velocity. Its SI unit is kg-m/s. Mathematically, it is given by :
v = 2 m/s
Therefore the initial speed of spaceship 1 is 2 m/s. Hence, this is the required solution.
Answer:
Explanation:
The resistance of a wire is given by:
where
is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire
1) The first wire has length L and cross-sectional area A. So, its resistance is:
2) The second wire has length twice the first one: 2L, and same thickness, A. So its resistance is
3) The third wire has length L (as the first one), but twice cross sectional area, 2A. So, its resistance is
By comparing the three expressions, we find
So, this is the ranking of the wire from most current (least resistance) to least current (most resistance).