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3 years ago

7

What is the best way to describe the rate of motion of an object that changes speed several times over a period of time is to ca

lculate

1 answer:

valentinak56 [21]3 years ago

4 0

It is to calculate the speed and the time.

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"relate the fertile phase of the menstrual cycle to the process of fertilisation"

DerKrebs [107]

Explanation:

During your menstrual cycle , Harmones make the eggs in your Ovaries mature -

• when an egg is mature , That means it's ready to be fertilized by a sperm cell .

• These hormones also make the lining of your uterus thick and spongy . So if your egg does get Fertilised , It has a nice cushy place to land and start a pregnancy .

<h3>Hope this helps </h3>

8 0

2 years ago

A microcomputer that is smaller, lighter, and less powerful than a notebook, and that has a touch sensitive screen, is called a

yKpoI14uk [10]

<span>A microcomputer that is smaller, lighter, and less powerful than a notebook, and that has a touch sensitive screen, is called a tablet. Tablets are used similarly to computers in the way that information can be stored, viewed and edited on them.</span>

8 0

3 years ago

A simple harmonic oscillator has amplitude 0.43 m and period 3.9 sec. What is the maximum acceleration?

rjkz [21]

Answer:

Maximum acceleration in the simple harmonic motion will be $0.854rad/sec^2$

Explanation:

We have given amplitude of simple harmonic motion is A = 0.43 m

Time period of the oscillation is T = 3.9 sec

We have to find the maximum acceleration

For this we have to find the angular frequency

Angular frequency will be equal to $\omega =\frac{2\pi }{T}=\frac{2\times 3.14}{3.9}=1.61rad/sec$

Maximum acceleration is given by $a_{max}=\omega ^2A=1.61^2\times 0.43=0.854rad/sec^2$

So maximum acceleration in the simple harmonic motion will be $0.854rad/sec^2$

8 0

3 years ago

Read 2 more answers

a certain projetor uses a concave mirror for projecting an object's image on a screen .it produces on image that is 4 times bigg

IrinaK [193]

Answer:

f = 1 m

Explanation:

The magnification of the lens is given by the formula:

$M = \frac{q}{p}$

where,

M = Magnification = 4

q = image distance = 5 m

p = object distance = ?

Therefore,

$4 = \frac{5\ m}{p}\\\\p = \frac{5\ m}{4}\\\\p = 1.25\ m$

Now using thin lens formula:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}\\\\\frac{1}{f} = \frac{1}{1.25\ m}+\frac{1}{5\ m}\\\\\frac{1}{f} = 1\ m^{-1}\\\\$

<u>f = 1 m</u>

6 0

3 years ago

An ion accelerated through a potential difference of 115 V experiences an increase in kinetic energy of 7.37 x 1017 J. Calculate

riadik2000 [5.3K]

Answer: $6.408(10)^{-19} C$

Explanation:

This problem can be solved by the following equation:

$\Delta K=q V$

Where:

$\Delta K=7.37(10)^{-17} J$ is the change in kinetic energy

$V=115 V$ is the electric potential difference

$q$ is the electric charge

Finding $q$ :

$q=\frac{\Delta K}{V}$

$q=\frac{7.37(10)^{-17} J}{115 V}$

Finally:

$q=6.408(10)^{-19} C$

4 0

3 years ago