Julianne’s displacement from her origin is equal to 10.015 kilometers.
<u>Given the following data:</u>
- Distance B = 8.5 km, Northeast.
To calculate Julianne’s displacement from her origin:
<h3>How to calculate displacement.</h3>
We would denote the two (2) unit vectors along the East and Northeast directions by i and j respectively.
<u>Note:</u> Northeast is at angle of 45° with the East.
In terms of vectors, the distances becomes:
Distance A = 2i
![Distance\;B=8.5 [(cos 45i + sin 45j)]\\\\Distance\;B=(\frac{8.5}{\sqrt{2} } i \;+\;\frac{8.5}{\sqrt{2} } j)](https://tex.z-dn.net/?f=Distance%5C%3BB%3D8.5%20%5B%28cos%2045i%20%2B%20sin%2045j%29%5D%5C%5C%5C%5CDistance%5C%3BB%3D%28%5Cfrac%7B8.5%7D%7B%5Csqrt%7B2%7D%20%7D%20i%20%5C%3B%2B%5C%3B%5Cfrac%7B8.5%7D%7B%5Csqrt%7B2%7D%20%7D%20j%29)
<u>For the </u><u>resultant displacement</u><u>:</u>
D = 10.015 kilometers.
Read more on displacement here: brainly.com/question/13416288
Answer: D) All of the above
Explanation:
Answer:
It is a parallel connection
Explanation:
In parallel connection the
Cell is not easily used up because the cells share the total current generated together with all bulbs.
But a major problem is the bulbs must not be left together undisconnected to avoid exhaustion arising from short fall in the strength of one cell as this bounds to affect others
Answer:
n = 1,875
Explanation:
The speed of light in vacuum is constant (c) and in a material medium it is
v = d / t
The refractive index of a material is defined by
n = c / v
Let's look for the speed of light in the material, in general the length that light travels is known, this value is high, x = 1, when we place a block on the road, a small amount is lengthened by the length of the block, which in general is despised
These measurements are made on a digital oscilloscope that allows to stop the signals and measure their differences, that is, the zero is taken when the first ray arrives and the time for the second ray is measured,
v = d / t
v = 1 / 6.25 10⁻⁹
v = 1.6 10⁸ m / s
we calculate the refractive index
n = 3 10⁸ / 1.6 10⁸
n = 1,875
If an experiment is conducted such that an applied force is exerted on an object, a student could use the graph to determine the net work done on the object.
The graph of the net force exerted on the object as a function of the object’s distance traveled is attached below.
- A student could use the graph to determine the net work done on the object by Calculating the area bound by the line of best fit and the horizontal axis from 0m to 5m
For more information on work done, visit
brainly.com/subject/physics
