(a) For the work-energy theorem, the work done to lift the can of paint is equal to the gravitational potential energy gained by it, therefore it is equal to

where m=3.4 kg is the mass of the can, g=9.81 m/s^2 is the gravitational acceleration and
is the variation of height. Substituting the numbers into the formula, we find

(b) In this case, the work done is zero. In fact, we know from its definition that the work done on an object is equal to the product between the force applied F and the displacement:

However, in this case there is no displacement, so d=0 and W=0, therefore the work done to hold the can stationary is zero.
(c) In this case, the work done is negative, because the work to lower the can back to the ground is done by the force of gravity, which pushes downward. Its value is given by the same formula used in part (a):

Answer:
The total amount after 3 years is = $ 2054.10
Explanation:
Given data
Principal Amount (P) = $ 1800
Rate of interest (R) = 4.5 %
Thus the total amount after 3 years compounded annually is given by the formula = P × ![[1 +\frac{R}{100} ]^{3}](https://tex.z-dn.net/?f=%5B1%20%2B%5Cfrac%7BR%7D%7B100%7D%20%20%5D%5E%7B3%7D)
⇒ 1800 × ![[1 +\frac{4.5}{100} ]^{3}](https://tex.z-dn.net/?f=%5B1%20%2B%5Cfrac%7B4.5%7D%7B100%7D%20%20%5D%5E%7B3%7D)
⇒ 2054.10
Thus the total amount after 3 years is = $ 2054.10
Compound interest earned in three years = 2054.10 - 1800 = $ 254.10
Explanation:
hope this helps you dear friend.
Answer:
Length, l = 33.4 m
Explanation:
Given that,
Electrical field, 
Let the electrical potential is, 
We need to find the length of a thundercloud lightning bolt. The relation between electric field and the electric potential is given by :

So, the length of a thundercloud lightning bolt is 33.4 meters. Hence, this is the required solution.
Answer:
the filling stops when the pressure of the pump equals the pressure of the interior air plus the pressure of the walls.
Explanation:
This exercise asks to describe the inflation situation of a spherical fultball.
Initially the balloon is deflated, therefore the internal pressure is equal to the pressure of the air outside, atmospheric pressure, when it begins to inflate the balloon with a pump this creates a pressure in the inlet valve and as it is greater than the pressure inside, the air enters it, this is repeated in each filling cycle, manual pump.
When the ball is full we have two forces, the one created by the external walls and the one aired by the pressure of the pump, these forces are directed towards the inside, but the air molecules exert a pressure towards the outside, which translates into a force. When these two forces are equal, the pump is no longer able to continue introducing air into the balloon.
Consequently the filling stops when the pressure of the pump equals the pressure of the interior air plus the pressure of the walls.