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nikitadnepr [17]
3 years ago
15

Starting from the front door of your ranch house, you walk 50.0m due east to your windmill, and then you turn around and slowly

walk 30.0m west to a bench where you sit and watch the sunrise. It takes you 27.0s to walk from your house to the windmill and then 39.0s to walk from the windmill to the bench.For the entire trip from your front door to the bench, what is your average velocity?For the entire trip from your front door to the bench, what is your average speed?
Physics
1 answer:
juin [17]3 years ago
8 0

Answer:

velocity = 0.3m/s

speed = 1.21 m/s

Explanation:

The total time it takes to get from the front door to the bench is

t = 27 + 39 = 66 seconds

The net displacement from the front door to the bench is the distance from the front door to the windmill subtracted by the distance from the windmill to the bench

s = 50 - 30 = 20 m

So the average velocity is net displacement divided by total time

v = s / t = 20 / 66 = 0.3 m/s

The total distance from the front door to the bench is the sum of distance from the front door to the windmill and the distance from the windmill to the bench

S = 50 + 30 = 80 m

So the average speed is total distance divided by total time

v = s / t = 80 / 66 = 1.21 m/s

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A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. If the disk starts from rest and is then brought in contact with a spinning rubber wheel, we observe that the disk gradually begins to rotate too. If after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 4.0 rad/s, find the average angular acceleration that the disk experiences. (Assume the positive direction is in the initial direction of rotation of the disk. Indicate the direction with the sign of your answer.)

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The expression for the angular acceleration of a disk that is in contact with a spinning wheel can be given as:

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\alpha =0.14 rad/s^2

Angular displacement of a disk can be calculated by using the formula:

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substituting 11.0 rad/s for \omega and t = 35 s ; we have:

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