Answer:
0.84 s
Explanation:
Step 1
Given information:
Mass of the ice (m) = 2.0 kg
Heat transfer rate (Q/T) = 793.0 kW
Latent heat of fusion of ice (Lf) = 334 kJ/kg

Substituting the corresponding values we have:

V^2 =U^2 +2AS
V^2 = 25 ^2 + 2x9.5x10
V^2 = 625 + 1900 = 2525
V = 50.25
Answer:
T = 676 N
Explanation:
Given that: f = 65 Hz, L = 2.0 m, and ρ = 5.0 g
= 0.005 kg
A stationary wave that is set up in the string has a frequency of;
f = 

⇒ T = 4
M
Where: t is the tension in the wire, L is the length of the wire, f is the frequency of the waves produced by the wire and M is the mass per unit length of the wire.
But M = L × ρ = (2 × 0.005) = 0.01 kg/m
T = 4 ×
×
× 0.01
= 4 × 4 ×4225 × 0.01
= 676 N
Tension of the wire is 676 N.
Answer:
α = 1.875 rad/s²
t = 8 s
Explanation:
α = ω²/2θ = 15²/(2(60)) = 1.875 rad/s²
t = ω/a = 15 / 1.875 = 8 s
The correct formula for calculating the tangential speed of an orbiting object is V(t)=wr.
V(t)= Tangential Speed
w= Angular Velocity
r= Radius of the Path
Hope this helps.