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Paha777 [63]
3 years ago
12

Suppose you just received a shipment of seven televisions. Four of the televisions are defective. If two televisions are randoml

y selected, compute the probability
that both televisions work. What is the probability at least oone of the two televisions does not work?
The probability that both televisions work is
(Round to three decimal places as needed.).
The probability that at least one of the two televisions does not work is
(Round to three decimal places as needed.)
e

Mathematics
1 answer:
kherson [118]3 years ago
4 0

Answer:

- What is the probability at least one of the two televisions does not work?

The probability at least one of the two televisions does not​ work is 0.8163

- The probability that both televisions work is?

The probability that both televisions work is 0.1837

Step-by-step explanation:

Total televisions are 7

Faulty televisions are 4

Number of televisions selected is 2

You might be interested in
Evaluate the integral Find the volume of material remaining in a hemisphere of radius 2 after a cylindrical hole ofradius 1 is d
algol13

You want to find the volume inside the hemisphere x^2+y^2+z^2=4 (i.e. inside the sphere but above the plane z=0) and outside the cylinder x^2+y^2=1. Call this region R.

In cylindrical coordinates, we have

\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_1^2\int_0^{\sqrt{4-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta

\displaystyle=2\pi\int_1^2 r\sqrt{4-r^2}\,\mathrm dr

\displaystyle=-\pi\int_3^0\sqrt u\,\mathrm du

(where u=4-r^2)

\displaystyle=\pi\int_0^3\sqrt u\,\mathrm du

=\dfrac{2\pi}3u^{3/2}\bigg|_0^3=2\sqrt3\,\pi

7 0
4 years ago
Evaluate the line integral, where c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)
Arada [10]

The value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)

<h3>What is integration?</h3>

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

The parametric equations for the line segment from (0, 0, 0) to (2, 3, 4)

x(t) = (1-t)0 + t×2 = 2t  

y(t) = (1-t)0 + t×3 = 3t

z(t) = (1-t)0 + t×4 = 4t

Finding its derivative;

x'(t) = 2

y'(t) = 3

z'(t) = 4

The line integral is given by:

\rm \int\limits_C {xe^{yz}} \, ds = \int\limits^1_0 {2te^{12t^2}} \, \sqrt{2^2+3^2+4^2} dt

 

\rm ds = \sqrt{2^2+3^2+4^2} dt

After solving the integration over the limit 0 to 1, we will get;

\rm \int\limits_C {xe^{yz}} \, ds = \dfrac{\sqrt{29}}{12}  (e^{12}-1)   or

= 73037.99 ≈ 73038

Thus, the value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)

Learn more about integration here:

brainly.com/question/18125359

#SPJ4

7 0
2 years ago
Please Help!!
meriva
Apperently someone deleted my question i was trying to see if you had understood what i was trying to help you on

6 0
3 years ago
No Links
Black_prince [1.1K]

Answer:

C

Step-by-step explanation:

A and B would be very expensive for 2 people, and D is too little, so C would be sensible! Hope this helps!

5 0
2 years ago
What is the area of the composite figure? ___ units^2
elena-14-01-66 [18.8K]

Answer:

  34 square units

Step-by-step explanation:

The figure can be considered to be a trapezoid with a rectangle removed.

The area of the trapezoid is ...

  A = (1/2)(b1 +b2)h

  A = (1/2)(10 +6)(5) = 40

The area of the rectangle is ...

  A = LW

  A = (3)(2) = 6

Then the area of the shaded portion of the figure is ...

  shaded area = trapezoid area - rectangle area

  = 40 - 6 = 34 . . . square units

7 0
3 years ago
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