Answer:
2.28 × 10^-3 mol/L
Explanation:
The equation for the equilibrium is
CN^- + H2O ⇌ HCN + OH^-
Ka = 4.9 × 10^-10
KaKb = Kw
4.9 × 10^-10 Kb = 1.00 × 10^-14
Kb = (1.00 × 10^-14)/(4.9 × 10^-10) = 2.05 × 10^-5
Now, we can set up an ICE table
CN^- + H2O ⇌ HCN + OH^-
I/(mol/L) 0.255 0 0
C/(mol/L) -x +x +x
E/(mol/L) 0.255 - x x x
Ka = x^2/(0.255 - x) = 2.05 × 10^-5
Check for negligibility
0.255/(2.05 × 10^-5) = 12 000 > 400. ∴ x ≪ 0.255
x^2 = 0.255(2.05 × 10^-5) = 5.20 × 10^-6
x = sqrt(5.20 × 10^-6) = 2.28 × 10^-3
[OH^-] = x mol/L = 2.28 × 10^-3 mol/L
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Once the student has finished his experiment, additional steps he may take are to analyze the data gathered and draw a conclusion, then publish his findings to be seen by his peers (other students).
<h3 /><h3>What comes after the experiment?</h3>
- Once an experiment is concluded, one must go over the data gathered.
- By this, we mean to analyze the information obtained through the experiment.
- This allows the student to draw a conclusion backed by evidence.
- Once complete, it is wise to share and discuss the findings with peers.
Therefore, we can confirm that once the experiment is completed, the most common action that follows is to draw a conclusion based on the analysis of the data gathered during the experiment, then discuss the findings with peers.
To learn more about experiments visit:
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Answer:
2.78 moles of water are produced.
Explanation:
Given data:
Number of moles of H₂O produced = ?
Number of moles of oxygen react = 3.25 mol
Solution:
Chemical equation:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Now we will compare the moles of water with oxygen.
O₂ : H₂O
7 : 6
3.25 : 6/7×3.25 = 2.78 mol
Answer:
Subtract the mass of the CuSO4⋅ 5H2O from the mass of CuSO4 is the right one