The minimum coefficient of friction to avoid slippage of the coin is 0.23.
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Minimum coefficient of friction</h3>
The minimum coefficient of friction can determined from the maximum speed of the coin.
ma = μmg
mv²/r = μmg
v²/r = μg
v² = μgr
μ = v²/(gr)
μ = (ωr)²/(gr)
μ = ω²r/g
μ = (7.95² x 0.035)/(9.8)
μ = 0.23
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Answer:
v = 2 v₁ v₂ / (v₁ + v₂)
Explanation:
The body travels the first half of the distance with velocity v₁. The time it takes is:
t₁ = (d/2) / v₁
t₁ = d / (2v₁)
Similarly, the body travels the second half with velocity v₂, so the time is:
t₂ = (d/2) / v₂
t₂ = d / (2v₂)
The average velocity is the total displacement over total time:
v = d / t
v = d / (t₁ + t₂)
v = d / (d / (2v₁) + d / (2v₂))
v = d / (d/2 (1/v₁ + 1/v₂))
v = 2 / (1/v₁ + 1/v₂)
v = 2 / ((v₁ + v₂) / (v₁ v₂))
v = 2 v₁ v₂ / (v₁ + v₂)
The first figure matches the description
Answer:
Magnification, m = -0.42
Explanation:
It is given that,
Height of diamond ring, h = 1.5 cm
Object distance, u = -20 cm
Radius of curvature of concave mirror, R = 30 cm
Focal length of mirror, f = R/2 = -15 cm (focal length is negative for concave mirror)
Using mirror's formula :
, f = focal length of the mirror
v = -8.57 cm
The magnification of a mirror is given by,
m = -0.42
So, the magnification of the concave mirror is 0.42. Thew negative sign shows that the image is inverted.