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Triss [41]
3 years ago
11

What type of wave is sound? a. longitudnal b. surface c. tranverse, or d.. light ? ?

Physics
2 answers:
AVprozaik [17]3 years ago
7 0

Answer:

Sound is a series of compression waves that moves through air or other materials. Sound waves are a longitudinal wave. The speed of sound is about 343 m/s which is much slower than the speed of light.

Explanation:

I hoped this helped

bagirrra123 [75]3 years ago
3 0
A longitudinal wave is a type of sound
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Volume??? velocity??????
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What force causes weight? How is weight affected as an object moves farther away from the center of the earth?
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Gravity affects weight of an object

Its weight reduces as it moves away from the center as gravity is strongest near the core and reduces as you move away

Hope this helps C:


3 0
3 years ago
Read 2 more answers
What is the frequency heard by a person driving at 15 m/s toward a factory whistle emitting a
zmey [24]

Answer:

835.29 Hz

Explanation:

When moving towards the source of sound, frequency will be given by

f*=f(vd+v)/v

Where f is the freqiency of the source, vd is the driving speed, v is the speed of sound in air, f* is the inkown frequency when moving forward.

Substituting 800 Hz for f, 340 m/s for v and 15 m/s for vd then

f*=800(15+340)/340=835.29411764704 Hz

Rounded off, the frequency is approximately 835.29 Hz

4 0
3 years ago
Calculate the moment of Inertia for a ring with a mass 0.715 kg, an inner radius of 10.7 cm and an outer radius of 12.7 cm.
lisov135 [29]
Using formula: 
I=(1/2)*M*(R^2+r^2) 

<span>I=0.5*0.715kg*[(12.7cm)^2+(10.7cm)^2] </span>

<span>I=98.6 kg*cm^2</span>
7 0
2 years ago
A rifle bullet with mass ma = 8.00 g strikes and embeds itself in a block with mass mb = 0.992 kg that rests on a frictionless,
Doss [256]

Answer:

the magnitude of the velocity of the block just after impact is 2.598 m/s and the original speed of the bullect is 324.76m/s.

Explanation:

a)  Kinetic energy of block = potential energy in spring  

½ mv² = ½ kx²

Here m stands for combined mass (block + bullet),

which is just 1 kg.  Spring constant k is unknown, but you can find it from given data:  

k = 0.75 N / 0.25 cm

= 3 N/cm, or 300 N/m.  

From the energy equation above, solve for v,

v = v √(k/m)  

= 0.15 √(300/1)

= 2.598 m/s.

b)  Momentum before impact = momentum after impact.

Since m = 1 kg,

v = 2.598 m/s,

p = 2.598 kg m/s.  

This is the same momentum carried by bullet as it strikes the block.  Therefore, if u is bullet speed,  

u = 2.598 kg m/s / 8 × 10⁻³ kg

= 324.76 m/s.

Hence, the magnitude of the velocity of the block just after impact is 2.598 m/s and the original speed of the bullect is 324.76m/s.

6 0
3 years ago
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