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Triss [41]
3 years ago
11

What type of wave is sound? a. longitudnal b. surface c. tranverse, or d.. light ? ?

Physics
2 answers:
AVprozaik [17]3 years ago
7 0

Answer:

Sound is a series of compression waves that moves through air or other materials. Sound waves are a longitudinal wave. The speed of sound is about 343 m/s which is much slower than the speed of light.

Explanation:

I hoped this helped

bagirrra123 [75]3 years ago
3 0
A longitudinal wave is a type of sound
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The change of motion of a body is proportional to the applied force, and it takes place in the direction of a straight line in w
7nadin3 [17]

Answer:

Newton's Second Law of Motion  

Explanation:

According to Newton's second law of motion, the change in velocity of a body is directly proportional to the force applied on it. Velocity is a vector quantity. It measures the magnitude of the speed as well as its direction.

F = m a

where, F is the applied force, m is the mass and a is the acceleration.

It can also be expressed as:

F = \frac{dp}{dt}

where, p = mv ( momentum)

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4 years ago
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A 20 cm long spring is attached to a wall. the spring stretches to a length of 22 cm when you pull on it with a force of 100 n.
liberstina [14]
This phenomenon can be describedby Hooke'slaw and expressed by the formula: F=k*deltax, where k is the spring's constant, and delta xis the displacement of the spring. Transposing the terms such that we want to know the value of k,

k = F/deltax = 100N/(22 cm - 20cm)
k = 50 N/cm
7 0
4 years ago
If there are no other changes, explain what effect reducing the mass of the car will have on its acceleration when starting to m
densk [106]

Answer:

when the mass of an object is decreased, the acceleration will increase

when mass is increased, acceleration decreases

3 0
3 years ago
A spring-loaded launcher has a mass of 0.60  kg and is placed on a platform 1.2m above the ground. The force of friction is negl
kobusy [5.1K]

Answer:

C The launcher will fall off the platform and land D/2 to the left of the platform because the launcher is twice the mass of the ball.

Explanation:

The figure is missing: you can find it in attachment.

We can apply the law of conservation of momentum to check that the launcher will leave the platform with a speed which is half the speed of the ball. In fact, the total initial momentum is zero:

p_i = 0

while the total final momentum is:

p_f = m_l v_l + m_b v_b

where

m_l = 0.60 kg is the mass of the launcher

m_b = 0.30 kg is the mass of the ball

v_l is the velocity of the launcher

v_b is the velocity of the ball

Since the total momentum must be conserved, p_i=p_f, so

0=m_l v_l + m_b v_b

Therefore we find

v_l = - \frac{m_b}{m_l}v_b = -\frac{0.30}{0.60}v_b = -\frac{v_b}{2}

which means that the launcher leaves the platform with a velocity which is half that of the ball, and in the opposite direction (to the left).

Since the distance covered by both the ball and the launcher only depends on their horizontal velocity, this also means that the launcher will cover half the distance covered by the ball before reaching the ground: therefore, since the ball covers a distance of D, the launcher will cover a distance of D/2.

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4 years ago
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That depends on which angle you picked first, because that determines
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If you picked the right angle (90°) first, before you asked the question,
then the other two are acute angles, and they're also complementary
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4 years ago
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