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Elden [556K]
3 years ago
9

Which term below best matches this definition - a period in European history when many educated people stressed the importance o

f learning and reasoning; education was considered the key to understanding and solving society's problems
Physics
1 answer:
german3 years ago
5 0

Answer:

The Enlightenment.

Explanation:

The Enlightenment took place during the eighteen century and it typically involved a period of philosophical, cultural and intellectual movement in which ideas on nature, reason, humanity and God were emphasized on greatly over science and superstition through meetings that were held at coffeeshops, scientific academies, literary salons, masonic lodges, etc. Some of the influential philosophers of the enlightenment were Adam Smith, John Locke, Jean Jacques Rousseau, David Hume, Baruch Spinoza, Montesquieu, Hugo Grotius, Denis Diderot, Gottfried Wilhelm, Cesare Beccaria, Immanuel Kant etc. The enlightenment was also known as the age of reason or the age of enlightenment.

Hence, the enlightenment was a period in European history when many educated people stressed the importance of learning and reasoning; education was considered the key to understanding and solving society's problems.

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Suppose astronomers built a 150-meter telescope. how much greater would its light-collecting area be than that of the 10-meter k
Dennis_Churaev [7]
Almost all telescopes have a circular mirror. The area of a circle is proportional to r^2 where r is the radius of the circle, the constant of proportionality being 4\pi
S =4\pi r^2
Therefore the area of 150 meter telescope would be 
S_1/S_2=(r_1/r_2)^2 =(75/5)^2 =15^2=225
times bigger than the area of the smaller (10 meter) telescope.

6 0
3 years ago
How do you make a iPad I can text and stuff and don't understand how
tigry1 [53]
Circuit board stuff
4 0
3 years ago
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A particle with positive charge q = 9.61 10-19 C moves with a velocity v = (5î + 4ĵ − k) m/s through a region where both a unifo
user100 [1]

Answer:

\vec{F}=(1.537*10^{-17}\hat{i}-9.61*10^{-19}\hat{j}-2.883*10^{-18}\hat{k})N

Explanation:

The total force on the particle is given by

\vec{F}=q\vec{v}\ X\ \vec{B}+q\vec{E}

Then, by replacing we have:

q\vec{v}\ X \vec{B}=q[7\hat{k}-9\hat{j}-\hat{k}]\\\\q\vec{E}=q[5\hat{i}-\hat{j}-2\hat{k}]\\\\\vec{F}=(9.61*10^{-19}C)[(7+9)\hat{i}+(-9-1)\hat{j}+(-1-2)\hat{k}]\\\\\vec{F}=(1.537*10^{-17}\hat{i}-9.61*10^{-19}\hat{j}-2.883*10^{-18}\hat{k})N

where the cross product can be made with the determinant method.

Hope this helps!!

3 0
3 years ago
Read 2 more answers
A coffee filter of mass 1.5 grams dropped from a height of 3 m reaches the ground with a speed of 0.7 m/s. How much kinetic ener
Mademuasel [1]

The kinetic energy gained by the air molecules is 0.0437 J                

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Given:

Mass of a coffee filter, m = 1.5 g

Height from which it is dropped, h = 3 m

Speed at ground, v = 0.7 m/s

Initially, the coffee filter has potential energy. It is given by :

P =mgh

P = 1.5 × 10⁻³ kg × 9.8 m/s² × 3m

P = 0.0441 J

Finally, it will have kinetic energy. It is given by :

E= \frac{1}{2} mv^{2}

E= \frac{1}{2}×1.4 × 10⁻³ × (0.7)²

E = 0.000343 J

The  kinetic energy Kair did the air molecules gain from the falling coffee filter is :

E = 0.000343 -  0.0441

  = 0.0437 J

So, the kinetic energy Kair did the air molecules gain from the falling coffee filter is 0.0437 J

Learn more about kinetic energy here:

brainly.com/question/8101588

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8 0
2 years ago
A student pushes a 0.2 kg box against a spring causing the spring to compress 0.15 m. When the spring is released, it will launc
german

Answer:

The maximum height the box will reach is 1.72 m

Explanation:

F = k·x

Where

F = Force of the spring

k = The spring constant = 300 N/m

x  = Spring compression or stretch = 0.15 m

Therefore the force, F of the spring = 300 N/m×0.15 m = 45 N

Mass of box = 0.2 kg

Work, W, done by the spring = \frac{1}{2} kx^2 and the kinetic energy gained by the box is given by KE = \frac{1}{2} mv^2

Since work done by the spring = kinetic energy gained by the box we have

\frac{1}{2} mv^2 =  \frac{1}{2} kx^2  therefore we have v = \sqrt{\frac{kx^2}{m} } = x\sqrt{\frac{k}{m} } = 0.15\sqrt{\frac{300}{0.2} } = 5.81 m/s

Therefore the maximum height is given by

v² = 2·g·h or h = \frac{v^2}{2g} = \frac{5.81^{2} }{2*9.81} = 1.72 m

6 0
3 years ago
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