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wlad13 [49]
3 years ago
6

A CD case slides along a floor in the positive direction of an x axis while an applied force a acts on it. The force is directed

along the x axis and has the x component Fax = 12x - 3x2, with x in meters and Fax in newtons. The case starts at rest at the position x = 0, and it moves until it is again at rest.
(A) Plot the work done on the case by a versus position x. (Do this on paper. Your instructor may ask you to turn in this work.)
(B) At what position is the work maximum?
(C) What is the maximum value of the work?
(D) At what position has the work decreased to zero?
(E) At what position is the case again at rest?
Physics
1 answer:
alisha [4.7K]3 years ago
4 0
Your answer should be b if I’m not mistaken
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Answer:

Chemical substances in food that have specific functions in your body are called Nutrients. Examples: proteins, fats, carbohydrates, vitamins, and minerals

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These chemical substances keep our body healthy.

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4 0
3 years ago
Suppose a police officer is 1/2 mile south of an intersection, driving north towards the intersection at 40 mph. At the same tim
blagie [28]

Answer:

75.36 mph

Explanation:

The distance between the other car and the intersection is,

x=x_{0}+V t \\ x=\frac{1}{2}+V t

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y=y_{0}+V t

y=\frac{1}{2}-40 t

(Negative sign indicates that he is moving towards the intersection)

Therefore the distance between them is given by,

z^{2}=x^{2}+y^{2}(\text { Using Phythogorous theorem })

z^{2}=\left(\frac{1}{2}+V t\right)^{2}+\left(\frac{1}{2}-40 t\right)^{2} \ldots \ldots \ldots(1)

The rate of change is,

2 z \frac{d z}{d t}=2\left(\frac{1}{2}+V t\right) V+2\left(\frac{1}{2}-40 t\right)(-40)

2 z \frac{d z}{d t}=V+2 V^{2} t-40+3200 t \ldots \ldots \ldots

Now finding z when t=0, from (1) we have

z^{2}=\left(\frac{1}{2}+V(0)\right)^{2}+\left(\frac{1}{2}-40(0)\right)^{2}

z^{2}=\frac{1}{4}+\frac{1}{4}=\frac{1}{2} \\ z=\sqrt{\frac{1}{2}} \approx 0.7071

The officer's radar gun indicates 25 mph pointed at the other car then, \frac{d z}{d t}=25 when t=0, from

From (2) we get

2(0.7071)(25)=V+2 V^{2}(0)-40+3200(0)

2(0.7071)(25)=V+2 V^{2}(0)-40

35.36=V-40

V=35.36+40=75.36

Hence the speed of the car is 75.36 mph

7 0
3 years ago
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B. Constant velocity


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3 years ago
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Answer:

2.85 s .

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8 0
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Answer:

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