in the same direction as the displacement vector and the motion
To find what a is, consider the equation v=at (v=velocity, a=acceleration, t=time interval), making a=v/t. Take the given v of 853m/s, and divide that by your time IN SECONDS, so 1.2ms=1.2*10^-3s.
a=(853)/(1.2*10^-3)=7.11*10^5 m/s^2.
Now Having F=ma, where a is your acceleration, and m=mass (which is 49*10^-3 kg),
F=(49*10^-3)(7.11*10^5)=3.48*10^4 N
Hope this helps!
Answer:
The length of the stick is 0.28 m.
The time the stick take to move is 0.97 ns.
Explanation:
Given that,
Relative speed of stick v= 0.96 c
Speed of light 
Proper length of stick = 1 m
We need to calculate the length of the stick
Using formula of length

Put the value into the formula



We need to calculate the time the stick take to move
Using formula of time

Put the value into the formula



Hence, The length of the stick is 0.28 m.
The time the stick take to move is 0.97 ns.
The magnitude of the force acting on the object lying on a flat surface without moving is 10 N.
The given parameters;
- magnitude of force on the object, F = 10 N
- angle between the object and the horizontal flat surface = 0⁰
Apply Newton's second law of motion to determine the magnitude of the force on the object.
Due to the position of the object, the magnitude of the force acting on it is calculated as;

Therefore, the magnitude of the force acting on the object is 10 N.
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