A CD case slides along a floor in the positive direction of an x axis while an applied force a acts on it. The force is directed
1 answer:
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Answer:
d = 68.5 x 10⁻⁶ m = 68.5 μm
Explanation:
The complete question is as follows:
An optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is 1.70m from the slits. If the slits are illuminated with coherent light of wavelength 633 nm, how far apart should the slits be?
The answer can be given by using the formula derived from Young's Double Slit Experiment:
where,
d = slit separation = ?
λ = wavelength = 633 nm = 6.33 x 10⁻⁷ m
L = distance from screen (detector) = 1.7 m
y = distance between bright fringes = 15.7 mm = 0.0157 m
Therefore,
<u>d = 68.5 x 10⁻⁶ m = 68.5 μm</u>
Velocity:
Velocity is change in displacement with respect to time:
Analysing the units, meters (displacement) and seconds (time) are basic units:
Therefore the unit of velocity is m/s
Force:
Newton's second law of motion:
Kilogram (mass) is a basic unit, and accelerations unit can be found using the equation:
Analysing the units:
Therefore, the unit of force is:
Pressure:
Pressure is given by the equation:
where S is area of effect, F is force
Area for a basic rectangle (geometric shape is arbitrary for dimensional analysis) is found by multiplying two lengths:
, the unit of area
Dividing the aforementioned unit of force by the unit of area:
, the unit of pressure
Work:
Work is given by the equation:
, (dot product may be assumed as normal multiplication for the purposes of unit analysis)
Knowing displacement's (x) unit is m:
, the unit of work.