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alexandr402 [8]
4 years ago
7

A pump contains 0.5 L of air at 203 kPa . You draw back on the piston of the pump, expanding the volume until the pressure reads

50.8 kPa . What is the new volume of air in the pump?
Physics
1 answer:
aksik [14]4 years ago
5 0

Answer:

V₂ = 2 L

Explanation:

given,

P₁ = 203 kPa

V₁ = 0.5 L

Now, volume is expanded

P₂ = 50.8 kPa

V₂ = ?

Using Boyle's law

 P₁V₁ = P₂ V₂

V_2 = \dfrac{P_1V_1}{P_2}

inserting all the values

V_2 = \dfrac{203\times 0.5}{50.8}

     V₂ = 2 L

Hence, new volume of air in the pump is equal to 2 L.

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Two loudspeakers are 1.60 m apart. A person stands 3.00 m from one speaker and 3.50 m from the other. (a) What is the lowest fre
VMariaS [17]

Answer:

Explanation:

Given

Distance between two loud speakers d=1.6\ m

Distance of person from one speaker x_1=3\ m

Distance of person from second speaker x_2=3.5\ m

Path difference between the waves is given by

x_2-x_1=(2m+1)\cdot \frac{\lambda }{2}

for destructive interference m=0 I.e.

x_2-x_1=\frac{\lambda }{2}

3.5-3=\frac{\lambda }{2}

\lambda =0.5\times 2

\lambda =1\ m

frequency is given by

f=\frac{v}{\lambda }

where v=velocity\ of\ sound\ (v=343\ m/s)

f=\frac{343}{1}=343\ Hz

For next frequency which will cause destructive interference is

i.e. m=1 and m=2

3.5-3=\frac{2\cdot 1+1}{2}\cdot \lambda

\lambda =\frac{1}{3}\ m

frequency corresponding to this is

f_2=\frac{343}{\frac{1}{3}}=1029\ Hz

for m=2

3.5-3=\frac{5}{2}\cdot \lambda

\lambda =\frac{1}{5}\ m

Frequency corresponding to this wavelength

f_3=\frac{343}{\frac{1}{5}}

f_3=1715\ Hz                        

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The higher density allows the protogalactic clouds to cool faster and form an elliptical galaxy rather than a spiral galaxy.

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Since there had been no previous star formation to create other elements, protogalaxies would have been made up almost entirely of hydrogen and helium. The hydrogen would bond to form H2 molecules, with some exceptions. This would change as star formation began and produced more elements through the process of nuclear fusion.

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To understand it better, regarding to the equivalence principle, Einstein formulated the following:  

A gravitational force and an acceleration in the opposite direction are equivalent, both have indistinguishable effects.  Because the laws of physics must be accomplished in all frames of reference.

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