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AnnZ [28]
4 years ago
8

A tuning fork is struck and is vibrating at a single frequency. If a second tuning fork with the same frequency is placed near t

he first it begins to vibrate. This is an example of _____.
resonance
forced vibration
beats
Doppler effect
Physics
2 answers:
irina1246 [14]4 years ago
6 0
Forced Vibration hope this helps :P
gladu [14]4 years ago
4 0

It is not forced vibrations just turned it in and was wrong.

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boyakko [2]

Answer:

i d k h b u lol I wish I knew it sorry

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3 years ago
Please help it’s urgent
Sidana [21]

Answer:

I believe it's sound energy.

Explanation:

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6 0
3 years ago
A laser source has a bandwidth of 30GHz (a) Calculate the coherence length of the source b) What is the time separation of secti
abruzzese [7]

Explanation:

It is given that,

Bandwidth of a laser source, f=30\ GHz=30\times 10^9\ Hz

(b) Let t is the time separation of sections of sections of the light wave that can still interfere. The time period is given by :

T=\dfrac{1}{f}

T=\dfrac{1}{30\times 10^9}

T=3.33\times 10^{-11}\ s

(a) Let h is the coherence length of the source. It is given by :

l=c\times T

c is the speed of light

l=3\times 10^8\times 3.33\times 10^{-11}

l = 0.0099 m

Hence, this is the required solution.

6 0
3 years ago
Which statement is the best interpretation of the ray diagram shown below?
kicyunya [14]
This correct answer would be C
5 0
3 years ago
A 2-kg toy car accelerates from 5 to 10 m/s.
andre [41]
<h3><u>Full Question:</u></h3>

A 2-kg toy car accelerates from 5 to 10 m/s in 2 seconds. Find the applied force.

<h2><u>Answer:</u></h2>

Force applied is 5\frac {kgm} {s^2}.

<h3><u>Explanation:</u></h3>

Force is defined as something which changes or tends to change the velocity of a body. And acceleration is defined as the rate of change of velocity of a body per time. Both of them are vector quantities.

The initial velocity of the body = 5 m/s.

The final velocity of the body = 10 m/s.

So the change in velocity = 10 - 5 m/s = 5m/s.

Time period = 2 seconds.

So acceleration =\frac52 m/s^2= 2.5 m/s^2

The force is defined as the product of mass and acceleration of the body.

Mass of body = 2 kg.

So, force applied =  2 \times 2.5 kgm/s^2. =5kgm/s^2.

4 0
3 years ago
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